在 ruby​​ 中以内置方式列出目录中的目录

Question

有没有更干净的内置方法来做到这一点？

ree> Pathname.new('/path/to').children.select{|e| e.directory?}.map{|d| d.basename.to_s}
 => ["test1", "test2"]

理想情况下，我想避免 directory? 调用

Answer 1

从Chandra的答案开始，根据您是否需要完整路径，您可以使用

Dir['app/*/']
# => ["app/controllers/", "app/helpers/", "app/metal/", "app/models/", "app/sweepers/", "app/views/"

Dir['app/*/'].map { |a| File.basename(a) }
# => ["controllers", "helpers", "metal", "models", "sweepers", "views"]

如果您使用Ruby >= 1.8.7，Chandra的答案也可以重写为

Pathname.glob('app/*/').map(&:basename)
# you can skip .to_s unless you don't need to work with strings
# remember you can always use a pathname as string for the most part of Ruby functions
# or interpolate the value

Answer 2

Pathname.glob("/path/to/*/").map { |i| i.basename.to_s }