excel 2003和excel 2007行、列地址差异

发布于 2024-08-16 08:25:26 字数 137 浏览 7 评论 0原文

在excel 2003中,行、列地址指定为A,1和C,12 但在 Excel 2007 中,这种格式更改为整数,例如 1,1 和 3,12

是否有任何内置支持将旧地址转换为新地址,或者是否有任何自定义算法来转换这些值。

提前致谢

in excel 2003 row,column addresses are specified like A,1 and C,12
but in excel 2007 this format changed to integers like 1,1 and 3,12

is there any built in support for converting old address to new one or is there any custom algorithm to convert these values.

thanks in advance

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︶ ̄淡然 2024-08-23 08:25:26

这是我们用来将 Excel 列字母与数字相互转换的方法

/// <summary>
/// 1 -> A<br/>
/// 2 -> B<br/>
/// 3 -> C<br/>
/// ...
/// </summary>
/// <param name="column"></param>
/// <returns></returns>
public static string ExcelColumnFromNumber(int column)
{
    string columnString = "";
    decimal columnNumber = column;
    while (columnNumber > 0)
    {
        decimal currentLetterNumber = (columnNumber - 1) % 26;
        char currentLetter = (char)(currentLetterNumber + 65);
        columnString = currentLetter + columnString;
        columnNumber = (columnNumber - (currentLetterNumber + 1)) / 26;
    }
    return columnString;
}

/// <summary>
/// A -> 1<br/>
/// B -> 2<br/>
/// C -> 3<br/>
/// ...
/// </summary>
/// <param name="column"></param>
/// <returns></returns>
public static int NumberFromExcelColumn(string column)
{
    int retVal = 0;
    string col = column.ToUpper();
    for (int iChar = col.Length - 1; iChar >= 0; iChar--)
    {
        char colPiece = col[iChar];
        int colNum = colPiece - 64;
        retVal = retVal + colNum * (int)Math.Pow(26, col.Length - (iChar + 1));
    }
    return retVal;
}

Here is what we use to convert Excel Column Letters to numbers and back

/// <summary>
/// 1 -> A<br/>
/// 2 -> B<br/>
/// 3 -> C<br/>
/// ...
/// </summary>
/// <param name="column"></param>
/// <returns></returns>
public static string ExcelColumnFromNumber(int column)
{
    string columnString = "";
    decimal columnNumber = column;
    while (columnNumber > 0)
    {
        decimal currentLetterNumber = (columnNumber - 1) % 26;
        char currentLetter = (char)(currentLetterNumber + 65);
        columnString = currentLetter + columnString;
        columnNumber = (columnNumber - (currentLetterNumber + 1)) / 26;
    }
    return columnString;
}

/// <summary>
/// A -> 1<br/>
/// B -> 2<br/>
/// C -> 3<br/>
/// ...
/// </summary>
/// <param name="column"></param>
/// <returns></returns>
public static int NumberFromExcelColumn(string column)
{
    int retVal = 0;
    string col = column.ToUpper();
    for (int iChar = col.Length - 1; iChar >= 0; iChar--)
    {
        char colPiece = col[iChar];
        int colNum = colPiece - 64;
        retVal = retVal + colNum * (int)Math.Pow(26, col.Length - (iChar + 1));
    }
    return retVal;
}
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