使用基本访问身份验证从 Python 读取 https url
如何在 Python 中打开 https url？
import urllib2
url = "https://user:[email protected]/path/
f = urllib2.urlopen(url)
print f.read()
给出：
httplib.InvalidURL: nonnumeric port: '[email protected]'
How do you open https url in Python?
import urllib2
url = "https://user:[email protected]/path/
f = urllib2.urlopen(url)
print f.read()
gives:
httplib.InvalidURL: nonnumeric port: '[email protected]'
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（4）
这从来没有让我失望过
This has never failed me
请阅读 urllib2 密码管理器和基本身份验证处理程序以及摘要身份验证处理程序。
http://docs.python.org/library/urllib2.html#abstractbasicauthhandler-objects
http://docs.python.org/library/urllib2.html #httpdigestauthhandler-objects
您的 urllib2 脚本实际上必须提供足够的信息来进行 HTTP 身份验证。用户名、密码、域名等
Please read about the urllib2 password manager and the basic authentication handler as well as the digest authentication handler.
http://docs.python.org/library/urllib2.html#abstractbasicauthhandler-objects
http://docs.python.org/library/urllib2.html#httpdigestauthhandler-objects
Your urllib2 script must actually provide enough information to do HTTP authentication. Usernames, Passwords, Domains, etc.
如果您想将用户名和密码信息传递给
urllib2，您需要使用HTTPBasicAuthHandler。这是一个向您展示如何操作的教程。
If you want to pass username and password information to
urllib2you'll need to use anHTTPBasicAuthHandler.Here's a tutorial showing you how to do it.
您无法像这样将凭据传递给 urllib2.open。在您的情况下，
user被解释为域名，而[email protected]被解释为端口号。You cannot pass credentials to
urllib2.openlike that. In your case,useris interpreted as the domain name, while[email protected]is interpreted as the port number.