将天数添加到特定日期

发布于 2024-08-15 09:55:42 字数 244 浏览 2 评论 0原文

许多例子都是关于在这一天添加天数。但是，如果我有不同的起始日，该怎么办？

例如（不起作用）：

$day='2010-01-23';

// add 7 days to the date above
$NewDate= Date('$day', strtotime("+7 days"));
echo $NewDate;

上面的例子不起作用。我应该如何通过在日期位置放置其他内容来更改起始日？

原文

Many examples are about adding days to this day. But how to do it, if I have different starding day?

For example (Does not work):

$day='2010-01-23';

// add 7 days to the date above
$NewDate= Date('$day', strtotime("+7 days"));
echo $NewDate;

Example above does not work. How should I change the starding day by putting something else in the place of Date?

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時窥 2024-08-22 09:55:42

对于基于您的代码的非常基本的修复：

$day='2010-01-23';

// add 7 days to the date above
$NewDate = date('Y-m-d', strtotime($day . " +7 days"));
echo $NewDate;

如果您使用 PHP 5.3+，您可以使用非常方便的新 DateTime 库：

$day = '2010-01-23';

// add 7 days to the date above
$NewDate = new DateTime($day);
$NewDate->add(new DateInterval('P7D');
echo $NewDate->format('Y-m-d');

我现在已经完全切换到使用 DateTime 自己，因为它非常方便强大的。您还可以在实例化时轻松指定时区，即new DateTime($time, new DateTimeZone('UTC'))。您可以使用 add() 和 sub() 方法通过 DateInterval 对象更改日期。这是文档：

For a very basic fix based on your code:

$day='2010-01-23';

// add 7 days to the date above
$NewDate = date('Y-m-d', strtotime($day . " +7 days"));
echo $NewDate;

If you are using PHP 5.3+, you can use the new DateTime libs which are very handy:

$day = '2010-01-23';

// add 7 days to the date above
$NewDate = new DateTime($day);
$NewDate->add(new DateInterval('P7D');
echo $NewDate->format('Y-m-d');

I've fully switched to using DateTime myself now as it's very powerful. You can also specify the timezone easily when instantiating, i.e. new DateTime($time, new DateTimeZone('UTC')). You can use the methods add() and sub() for changing the date with DateInterval objects. Here's documentation:

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久夏青 2024-08-22 09:55:42

$NewDate = date('Y-m-d', strtotime('+7 days', strtotime($day)));

$NewDate = date('Y-m-d', strtotime('+7 days', strtotime($day)));

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您的好友蓝忘机已上羡 2024-08-22 09:55:42

来自 php.com binupillai2003

<?php
/*
Add day/week/month to a particular date
@param1 yyyy-mm-dd
@param1 integer
by Binu V Pillai on 2009-12-17
*/

function addDate($date,$day)//add days
{
$sum = strtotime(date("Y-m-d", strtotime("$date")) . " +$day days");
$dateTo=date('Y-m-d',$sum);
return $dateTo;
}

?>

From php.com binupillai2003

<?php
/*
Add day/week/month to a particular date
@param1 yyyy-mm-dd
@param1 integer
by Binu V Pillai on 2009-12-17
*/

function addDate($date,$day)//add days
{
$sum = strtotime(date("Y-m-d", strtotime("$date")) . " +$day days");
$dateTo=date('Y-m-d',$sum);
return $dateTo;
}

?>

回复收藏 0 原文

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