在 DOS 中获取文件同一行的输出？
如果我想将两个来源的输出放在同一行上，我该怎么做？
就我而言，我有一个文件和一个程序。该文件是这样的：
listOfThings=
我的程序在一行上输出字符串列表。我想要一个每晚运行的小脚本，将这两件事放在一行上。我无法弄清楚如何正确执行此操作，但
示例批处理文件
type header.txt > outputfile.txt
myProgram >> outputfile.txt
会导致以下结果：
listOfThings=
foo bar baz etc
我确实需要输出文件将列表立即跟在 = 之后，但我不知道如何使用 > 来做到这一点>操作员。 （在有人建议之前，我不能做类似在 listOfThings= 行末尾添加 \ 的事情，这对我想做的事情不起作用）
If I have output from two sources that I want to put together on the same line, how would I do that?
In my case I have a file and a program. The file is something like this:
listOfThings=
My program outputs a list of strings on a single line. I want have a small script that runs nightly to put these two things together on a single line. I can't figure out how to do this right though
example batch file
type header.txt > outputfile.txt
myProgram >> outputfile.txt
which results in this:
listOfThings=
foo bar baz etc
I really need the output file to have the list immediately follow the =, but I can't figure out how to do it with the >> operator. (and before anyone suggests it, I can't do something like put a \ on the end of the listOfThings= line, that won't work for what I'm trying to do)
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评论（2）
您需要确保 header.txt 的内容中没有回车换行符对。用十六进制编辑器查看并确保其中没有 0x0d0a。
You need to make sure that the contents of header.txt does not have a carriage return linefeed pair in it. Look at it with a hex editor and make sure there is no 0x0d0a in it.
您是否确保 header.txt 中根本没有任何行分隔符？ （即，= 是文件的最后一个字节）。
另外，请尝试将 header.txt 复制到 outputfile.txt，以防 type 自行附加换行符。
Have you made sure that header.txt doesn't have any line separators in it at all? (Ie, the = is the very last byte of the file).
Also, try copying header.txt to outputfile.txt in case type is appending a line feed on it's own.