如何以编程方式使可可应用程序处于活动状态
我有一个后台进程，当按下热键时，会出现一个透明窗口：
[window makeKeyAndOrderFront:nil];
[[content animator] setAlphaValue:1.0]; // alpha was 0.0
...窗口显示良好&在其他窗口前面（正如我想要的那样），但是直到我手动单击该窗口之前，窗口出现时处于活动状态的任何应用程序都保持活动状态。我期望“makeKeyAndOrderFront”也使应用程序处于活动状态，但是向我的 -applicationWillBecomeActive 添加 NSLog 行显示在执行鼠标单击之前它不会收到任何活动通知。
有谁知道如何在发出 -makeKeyAndOrderFront 的同时将我的应用程序设置为活动状态？我需要它处于活动状态，以便它可以开始接受键盘输入 - 需要任何帮助:-)
I've got a background process that makes a transparent window appear when a hotkey is pressed:
[window makeKeyAndOrderFront:nil];
[[content animator] setAlphaValue:1.0]; // alpha was 0.0
... the window shows up fine & in front of the other windows (as I want it to), however until I manually click the window whatever application was active when the window appears remains active. I was expecting the 'makeKeyAndOrderFront' to make the application active as well, however adding a NSLog line to my -applicationWillBecomeActive shows it's not getting any active notification until the mouse click is performed.
Does anyone know how I can set my application active @ the same time I issue the -makeKeyAndOrderFront ? I need it active so that it can begin accepting keyboard input - any assistance needed :-)
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[[NSApplication sharedApplication] activateIgnoringOtherApps : YES];。Look at
[[NSApplication sharedApplication] activateIgnoringOtherApps : YES];.对于 10.6 或更高
For 10.6 or greater
@Arvin 答案的 Swift 4.2+
Swift 4.2+ of @Arvin answer