有效的区域设置名称
如何找到有效的区域设置名称？
我目前使用的是 MAC OS X。
但有关其他平台的信息也很有用。
#include <fstream>
#include <iostream>
int main(int argc,char* argv[])
{
try
{
std::wifstream data;
data.imbue(std::locale("en_US.UTF-16"));
data.open("Plop");
}
catch(std::exception const& e)
{
std::cout << "Exception: " << e.what() << "\n";
throw;
}
}
% g++ main.cpp
% ./a.out
Exception: locale::facet::_S_create_c_locale name not valid
Abort
How do you find valid locale names?
I am currently using MAC OS X.
But information about other platforms would also be useful.
#include <fstream>
#include <iostream>
int main(int argc,char* argv[])
{
try
{
std::wifstream data;
data.imbue(std::locale("en_US.UTF-16"));
data.open("Plop");
}
catch(std::exception const& e)
{
std::cout << "Exception: " << e.what() << "\n";
throw;
}
}
% g++ main.cpp
% ./a.out
Exception: locale::facet::_S_create_c_locale name not valid
Abort
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构造函数调用 std::locale("") 创建一个代表用户偏好的 locale 对象。标准没有说明这意味着什么，但在许多系统上，库会替换环境变量中找到的任何内容（通常是
LANG或LC_ALL）来代替空字符串。例如，美国语言环境的通用名称是“en_US”。 （在 POSIX 系统上，您可以键入locale -a来列出支持的区域设置的名称。）locale -a应该适合您。如果您的意思是从 C++ std 库以编程方式，我不确定。
这个堆栈溢出问题可能也相关但他似乎并没有太多的反应。
编辑
要使用UTF-16，您可能需要使用libiconv如这个问题。
This page says:
The constructor call std::locale("") creates a locale object that represents the user's preferences. The standard doesn't say what this means, but on many systems the library substitutes whatever is found in an environment variable (often
LANGorLC_ALL) in place of the empty string. A common name for the American locale, for example, is "en_US". (On POSIX systems you can typelocale -ato list the names of supported locales.)locale -ashould work for you.If you mean programatically from the C++ std libary I'm not sure.
This stack overflow question is probably also relevant, but he doesn't seem to have had much response.
Edit
To use UTF-16 you probably will need to use libiconv as mentioned in this question.