C# - HttpWebRequest - POST

Question

我正在尝试向 Apache Web 服务器发送 Http POST。

我发现似乎需要设置 ContentLength 才能使请求正常工作。

我宁愿直接从 GetRequestStream() 创建一个 XmlWriter 并将 SendChunked 设置为 true，但这样做时请求会无限期挂起。

以下是我的请求的创建方式：

    private HttpWebRequest MakeRequest(string url, string method)
    {
        HttpWebRequest request = HttpWebRequest.Create(url) as HttpWebRequest;
        request.Method = method;
        request.Timeout = Timeout; //Property in my class, assume it's 10000
        request.ContentType = "text/xml"; //I am only writing xml with XmlWriter
        if (method != WebRequestMethods.Http.Get)
        {
            request.SendChunked = true;
        }
        return request;
    }

How can I make SendChunked work so I don't have set ContentLength?我不认为有理由在将 XmlWriter 的字符串发送到服务器之前将其存储在某处。

编辑：这是导致问题的我的代码：

    using (Stream stream = webRequest.GetRequestStream())
    {
        using (XmlWriter writer = XmlWriter.Create(stream, XmlTags.Settings))
        {
            Generator.WriteXml<TRequest>(request, writer);
        }
    }

在我没有使用从 GetRequestStream() 返回的 Stream 对象之前，我假设 XmlWriter 在处理时关闭了流，但事实并非如此。

下面的答案之一，让我来回答一下。我会将它们标记为答案。

就 HttpWebRequest 而言，我的原始代码工作得很好。

Answer 1

这应该按照你写的方式工作。我们能看到实际执行上传的代码吗？您记得关闭流吗？

Answer 2

查看示例 http://msdn.microsoft .com/en-us/library/system.net.httpwebrequest.sendchunked.aspx 他们仍然设置内容长度。实际上，最重要的是，如果您要发送数据，您需要告诉接收者您将发送多少数据。为什么在发送请求之前不知道要发送多少数据？

内容长度：

属性值
类型：系统..::.Int64
发送到 Internet 资源的数据字节数。默认值为 -1，表示该属性尚未设置，并且没有要发送的请求数据。

为 Aaron 编辑（我错了）：

HttpWebRequest httpWebRequest = HttpWebRequest.Create("http://test") as HttpWebRequest;
httpWebRequest.SendChunked = true;
MessageBox.Show("|" + httpWebRequest.TransferEncoding + "|");

来自 System.Net.HttpWebRequest.SerializeHeaders()：

if (this.HttpWriteMode == HttpWriteMode.Chunked)
{
    this._HttpRequestHeaders.AddInternal("Transfer-Encoding", "chunked");
}
else if (this.ContentLength >= 0L)
{
    this._HttpRequestHeaders.ChangeInternal("Content-Length", this._ContentLength.ToString(NumberFormatInfo.InvariantInfo));
}

Answer 3

我更喜欢使用通用方法来遵守此类内容。查看下面的 XML 发送方请求。它将序列化您的 XML，然后使用适当的 ContentType 发送它：

public bool SendXMLRequest<T>(T entity, string url, string method)
{
    HttpWebResponse response = null;
    bool received = false;
    try
    {
        var request = (HttpWebRequest)WebRequest.Create(url);
        var credCache = new CredentialCache();
        var netCred = new NetworkCredential(YOUR_LOGIN_HERE, YOUR_PASSWORD_HERE, YOUR_OPTIONAL_DOMAIN_HERE);
        credCache.Add(new Uri(url), "Basic", netCred);
        request.Credentials = credCache;
        request.Method = method;
        request.ContentType = "application/xml";
        request.SendChunked = "GET" != method.ToUpper();

        using (var writer = new StreamWriter(request.GetRequestStream()))
        {
            XmlSerializer serializer = new XmlSerializer(typeof(T));

            using (StringWriter textWriter = new Utf8StringWriter())
            {
                serializer.Serialize(textWriter, entity);
                var xml = textWriter.ToString();
                writer.Write(xml);
            }
        }

        response = (HttpWebResponse)request.GetResponse();    
        received = response.StatusCode == HttpStatusCode.OK; //YOu can change the status code to check. May be created, etc...
    }
    catch (Exception ex) { }
    finally
    {
        if(response != null)
            response.Close();
        }

    return received;
}