Stripes:我可以预先填充表单,但提交后 formBean 为空

发布于 2024-08-13 21:05:34 字数 2458 浏览 7 评论 0原文

我可以使用一个对象(在本例中为 client)预先填充我的 Stripes JSP 表单,但是当我提交此表单时,我的对象将返回 null。

我创建了第二个“temp”对象,它是 client 的并行副本,并且保留其值,因此我看不到在请求中传递对象的问题

的表单如下:

<s:form beanclass="com.jameselsey.salestracker.action.ViewClientAction">
            <s:hidden name="clientA" value="${actionBean.clientA}"/>
            <s:hidden name="clientId" value="${actionBean.clientId}"/>

            <table>
                <tr>
                    <td>Name : </td>
                    <td><s:text name="client.name"/></td>
                </tr>
                <tr>
                    <td>Sector : </td>
                    <td><s:text name="client.sector"/></td>
                </tr>
              <!-- omitted some attirbutes, not needed here -->
            </table>
        </s:form>

我 操作看起来像

public class ViewClientAction extends BaseAction
{

    @SpringBean
    ClientService clientService;// = new ClientService();
    private Integer clientId;
    private Client client;
    private Client clientA;

    public void setClient(Client client)
    {
        this.client = client;
    }
    public Integer getClientId()
    {
        return clientId;
    }

    public void setClientId(Integer clientId)
    {
        this.clientId = clientId;
    }

    public Client getClientA()
    {
        return clientA;
    }

    public void setClientA(Client clientA)
    {
        this.clientA = clientA;
    }



    public Client getClient()
    {
        return client;
    }

    @DefaultHandler
    public Resolution quickView()
    {
        clientA = clientService.getClientById(clientId);
        client = clientService.getClientById(clientId);
        return new ForwardResolution("/jsp/viewClientQuickView.jsp");
    }

    public Resolution save()
    {
        clientService.persistClient(client);
        return new ForwardResolution("/jsp/reports.jsp");
    }

    public Resolution viewClientInfo()
    {
        client = clientService.getClientById(clientId);
        return new ForwardResolution("/jsp/viewClientClientInfo.jsp");
    }
...

如果我在 clientService.persistClient(client); 设置断点,我可以看到 ClientA 具有对象的所有原始值,但 client 为空。

我是否错过了将表单 bean 绑定到操作中的 client 对象的某些内容?

谢谢

I can pre-populate my Stripes JSP form with an object, client in my case, but when I submit this form, my object is returning as null.

I have created a second "temp" object that is a parallel duplicate of client and this retains its values, so I can't see an issue passing an object in the request

My form is as follows :

<s:form beanclass="com.jameselsey.salestracker.action.ViewClientAction">
            <s:hidden name="clientA" value="${actionBean.clientA}"/>
            <s:hidden name="clientId" value="${actionBean.clientId}"/>

            <table>
                <tr>
                    <td>Name : </td>
                    <td><s:text name="client.name"/></td>
                </tr>
                <tr>
                    <td>Sector : </td>
                    <td><s:text name="client.sector"/></td>
                </tr>
              <!-- omitted some attirbutes, not needed here -->
            </table>
        </s:form>

My action looks like

public class ViewClientAction extends BaseAction
{

    @SpringBean
    ClientService clientService;// = new ClientService();
    private Integer clientId;
    private Client client;
    private Client clientA;

    public void setClient(Client client)
    {
        this.client = client;
    }
    public Integer getClientId()
    {
        return clientId;
    }

    public void setClientId(Integer clientId)
    {
        this.clientId = clientId;
    }

    public Client getClientA()
    {
        return clientA;
    }

    public void setClientA(Client clientA)
    {
        this.clientA = clientA;
    }



    public Client getClient()
    {
        return client;
    }

    @DefaultHandler
    public Resolution quickView()
    {
        clientA = clientService.getClientById(clientId);
        client = clientService.getClientById(clientId);
        return new ForwardResolution("/jsp/viewClientQuickView.jsp");
    }

    public Resolution save()
    {
        clientService.persistClient(client);
        return new ForwardResolution("/jsp/reports.jsp");
    }

    public Resolution viewClientInfo()
    {
        client = clientService.getClientById(clientId);
        return new ForwardResolution("/jsp/viewClientClientInfo.jsp");
    }
...

If I set a breakpoint at clientService.persistClient(client); I can see that ClientA has all of the original values of the object, yet client is nulled.

Have I missed something that binds the form bean to the client object in my action?

Thanks

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(2

烟柳画桥 2024-08-20 21:05:34

在您的 JSP 中添加以下行:

    <s:hidden name="client" value="${actionBean.client}"/>

Add this line in your JSP:

    <s:hidden name="client" value="${actionBean.client}"/>
初心未许 2024-08-20 21:05:34

我通过添加 @Before 方法来重新水合嵌套对象来实现此场景。之后,保存就可以正常工作了

@Before(stages = LifecycleStage.BindingAndValidation)
public void rehydrate() {
   if (context.getRequest().getParameter("save")!=null){
       this.domainObject = getHibernateSession().load(DomainObject.class, context.getRequest().getParameter("id"));
   }
}

public void save(){
    Session session=getHibernateSession();
    session.update(domainObject);
    session.commit();
    //...
}

I got this scenario working by adding a @Before method to re-hydrate the nested object. After this, save works properly

@Before(stages = LifecycleStage.BindingAndValidation)
public void rehydrate() {
   if (context.getRequest().getParameter("save")!=null){
       this.domainObject = getHibernateSession().load(DomainObject.class, context.getRequest().getParameter("id"));
   }
}

public void save(){
    Session session=getHibernateSession();
    session.update(domainObject);
    session.commit();
    //...
}
~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文