外键和 MySQL 错误
我有以下脚本在 MySQL 5.1 版本中创建一个表,该表引用其他 3 个表。所有 3 个表都是使用 InnoDB 创建的,并且所有 3 个表的 ID 列都定义为 INT。
我已经成功创建了引用 ACCOUNT 和 PERSON 的其他表,但是,这是第一个引用 ADDRESS 的表,因此我也包含了该表的定义,如下所示。
我收到的错误是 ERROR 1005 (HY000),errno 150,据我所知,这与外键创建有关。
失败的脚本是(为了简单起见,删除了额外的列):
CREATE TABLE WORK_ORDER (
ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
ACCOUNT_ID INT NOT NULL,
CUSTOMER_ID INT NOT NULL,
SALES_ID INT,
TRADES_ID INT,
LOCATION_ID INT NOT NULL,
INDEX CUST_INDEX(CUSTOMER_ID),
INDEX SALES_INDEX(SALES_ID),
INDEX TRADES_INDEX(TRADES_ID),
INDEX ACCOUNT_INDEX(ACCOUNT_ID),
INDEX LOCATION_INDEX(LOCATION_ID),
FOREIGN KEY (CUSTOMER_ID) REFERENCES PERSON(ID) ON DELETE CASCADE,
FOREIGN KEY (SALES_ID) REFERENCES PERSON(ID) ON DELETE SET NULL,
FOREIGN KEY (TRADES_ID) REFERENCES PERSON(ID) ON DELETE SET NULL,
FOREIGN KEY (ACCOUNT_ID) REFERENCES ACCOUNT(ID) ON DELETE CASCADE,
FOREIGN KEY (LOCATION_ID) REFERENCES ADDRESS(ID) ON DELETE SET NULL
) ENGINE=InnoDB;
用于创建 ADDRESS 表的 SQL 语句如下(为了简单起见,删除了额外的列)。
CREATE TABLE ADDRESS (
ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
PERSON_ID INT NOT NULL,
ACCOUNT_ID INT NOT NULL,
ADDRESS_L1 VARCHAR(50),
ADDRESS_L2 VARCHAR(50),
CITY VARCHAR(25),
PROVINCE VARCHAR(20),
POSTAL_CODE VARCHAR(6),
COUNTRY VARCHAR(25),
INDEX CUST_INDEX(PERSON_ID),
INDEX ACCOUNT_INDEX(ACCOUNT_ID),
FOREIGN KEY (ACCOUNT_ID) REFERENCES ACCOUNT(ID) ON DELETE CASCADE,
FOREIGN KEY (PERSON_ID) REFERENCES PERSON(ID) ON DELETE CASCADE
) ENGINE=InnoDB;
我在这里浏览了几个处理类似问题的问题,但大多数似乎是重复的定义和不匹配的字段类型,以及一些未对其中一个或另一个表使用 InnoDB 的问题。然而,这些似乎都不是问题。有什么想法吗?
I have the following script to create a table in MySQL version 5.1 which is to refer to 3 other tables. All 3 tables have been created using InnoDB, and all 3 tables have the ID column defined as INT.
I have created other tables successfully which reference ACCOUNT and PERSON, however, this is the first table which references ADDRESS, so I've included the definition for that table, as run, below as well.
The error which I'm getting is ERROR 1005 (HY000) with errno 150, which I understand to be relating to foreign key creation.
The script which fails is (extra columns removed for simplicity):
CREATE TABLE WORK_ORDER (
ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
ACCOUNT_ID INT NOT NULL,
CUSTOMER_ID INT NOT NULL,
SALES_ID INT,
TRADES_ID INT,
LOCATION_ID INT NOT NULL,
INDEX CUST_INDEX(CUSTOMER_ID),
INDEX SALES_INDEX(SALES_ID),
INDEX TRADES_INDEX(TRADES_ID),
INDEX ACCOUNT_INDEX(ACCOUNT_ID),
INDEX LOCATION_INDEX(LOCATION_ID),
FOREIGN KEY (CUSTOMER_ID) REFERENCES PERSON(ID) ON DELETE CASCADE,
FOREIGN KEY (SALES_ID) REFERENCES PERSON(ID) ON DELETE SET NULL,
FOREIGN KEY (TRADES_ID) REFERENCES PERSON(ID) ON DELETE SET NULL,
FOREIGN KEY (ACCOUNT_ID) REFERENCES ACCOUNT(ID) ON DELETE CASCADE,
FOREIGN KEY (LOCATION_ID) REFERENCES ADDRESS(ID) ON DELETE SET NULL
) ENGINE=InnoDB;
The SQL statement used to create the ADDRESS table is below (extra columns removed for simplicity).
CREATE TABLE ADDRESS (
ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
PERSON_ID INT NOT NULL,
ACCOUNT_ID INT NOT NULL,
ADDRESS_L1 VARCHAR(50),
ADDRESS_L2 VARCHAR(50),
CITY VARCHAR(25),
PROVINCE VARCHAR(20),
POSTAL_CODE VARCHAR(6),
COUNTRY VARCHAR(25),
INDEX CUST_INDEX(PERSON_ID),
INDEX ACCOUNT_INDEX(ACCOUNT_ID),
FOREIGN KEY (ACCOUNT_ID) REFERENCES ACCOUNT(ID) ON DELETE CASCADE,
FOREIGN KEY (PERSON_ID) REFERENCES PERSON(ID) ON DELETE CASCADE
) ENGINE=InnoDB;
I've browsed through several questions here dealing with similar issues, but most seem to be duplicate definitions and non-matching field types, as well as some not using InnoDB for one or the other of the tables. However, none of these seem to be the problem. Any ideas?
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您始终可以发出“SHOW ENGINE INNODB STATUS”命令。隐藏在输出中的是“LATEST FOREIGN KEY ERROR”部分,其中包含导致“150”错误的确切原因的更多详细信息:
You can always issue a 'SHOW ENGINE INNODB STATUS' command. Buried in the output will be a "LATEST FOREIGN KEY ERROR" section, which will have more details on exactly what caused the '150' error: