在Lua中，如何删除表中的表？

发布于 2024-08-13 02:21:35 字数 271 浏览 4 评论 0原文

例如：

items = {
    [753] = {
    },
    [192] = {
    },
    [789] = {
    },
    [791] = {
    },
    [790] = {
    },
    [776] = {
    },
}

我想删除789和其中的所有数据。我都尝试过：表. 删除( 项目, 2 );和 table.remove( items, 789 ); （我不确定索引是如何工作的）但运气不好。

原文

For example:

items = {
    [753] = {
    },
    [192] = {
    },
    [789] = {
    },
    [791] = {
    },
    [790] = {
    },
    [776] = {
    },
}

I would like to remove 789 and all data inside of it. I tried both:
table.remove( items, 2 ); and table.remove( items, 789 ); ( I wasn't sure how the indexing worked ) with no luck.

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月下伊人醉 2024-08-20 02:21:35

就像

items[789] = nil

在 Lua 中一样简单，如果表中的某个键具有 nil 值，那么就好像该键不存在一样。

> t = { [5] = {}, [10] = {} }
> for k,v in pairs(t) do print(k,v) end
5       table: 0037CBC0
10      table: 0037CBE8
> t[5] = nil
> for k,v in pairs(t) do print(k,v) end
10      table: 0037CBE8

另请参阅Lua 编程，第 2.5 节。（尽管在线版本是为Lua 5.0编写的，但这仍然适用于Lua 5.1）

...您可以将 nil 分配给表字段以将其删除。

当您将 nil 分配给索引时，这不会显式删除以前存储在该索引中的内容；而是会删除该索引中以前存储的内容。但它确实降低了存储在那里的引用计数，可能使其符合垃圾回收的条件。

It's as easy as

items[789] = nil

In Lua, if a key in a table has a nil value, then it's as though the key does not exist.

> t = { [5] = {}, [10] = {} }
> for k,v in pairs(t) do print(k,v) end
5       table: 0037CBC0
10      table: 0037CBE8
> t[5] = nil
> for k,v in pairs(t) do print(k,v) end
10      table: 0037CBE8

See also Progamming in Lua, section 2.5. (Even though the online version is written for Lua 5.0, this still applies to Lua 5.1)

... you can assign nil to a table field to delete it.

When you assign nil to your index, that doesn't explicitly delete what was previously stored in that index; but it does lower the reference count for what was stored there, potentially making it eligible for garbage collection.

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