管理旋转移动栅格地图

发布于 2024-08-12 20:57:54 字数 342 浏览 3 评论 0原文

我的应用程序呈现一个(光栅)移动地图。 我需要能够显示基于任何给定角度旋转的地图。 该程序当前使用 VC++/MFC,但问题是通用的。 我有一个源位图(CBitmap 或 HBITMAP),并使用 StretchBlt 将其绘制到设备上下文 (CDC)。 虽然对于angle=0(并且用户可以用鼠标平滑地抓取地图),这可以快速且平滑地工作,但如果我尝试旋转位图然后呈现它(使用 SetWorldTransform() 旋转位图),则情况并非如此大约需要数百毫秒,这太慢了)。

我认为解决方案是能够仅与当前屏幕上的像素相关,而不是旋转原始源位图 - 这是关键。

如果有人有类似实施的经验,那么它可能会节省我大量的试错工作。 谢谢! 阿维。

My application present a (raster) moving map.
I need to be able to show the map rotated base on any given angle.
The program is currently in VC++/MFC but the problem is generic.
I have a source bitmap (CBitmap or HBITMAP) and draw it to the device context (CDC) using StretchBlt.
While this works fast and smooth for angle=0 (and the user can grab the map smoothly with the mouse), this is not the case if I try to rotate the bitmap and then present it (the rotation of the bitmap using SetWorldTransform() or so takes hundreds of miliseconds and this is too slow).

I think that the solution is to be able to relate only to the pixels that currently on the screen and not rotating the original source bitmap - and this is the key.

If someone has experience with similar implementation then it might save me lots of trial and error efforts.
Thanks!
Avi.

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评论(2

撞了怀 2024-08-19 20:57:54

看起来 SetWorldTransform 非常慢:
http://www.codeguru.com/Cpp/GM/ bitmap/specialeffects/article.php/c1743

虽然该文章中提供的其他选项速度更快,但当然还有其他更好的解决方案,如下所示:
http://www.codeguru.com/cpp/gm/gdi /article.php/c3693/ (也请检查评论中的修复和改进)

此外,这里还有一些非 Windows 中心的快速旋转算法:
http://www.ddj.com/windows/184416337?pgno=11

请注意,如果您保证 2 维的能力,您可以获得显着的速度提升。

It looks like SetWorldTransform is extremely slow:
http://www.codeguru.com/Cpp/G-M/bitmap/specialeffects/article.php/c1743

And while the other options presented in that article are faster, there are of course other better solutions like this:
http://www.codeguru.com/cpp/g-m/gdi/article.php/c3693/ (check the comments for fixes and improvements as well)

Also here are some non-Windows centric fast rotation algorithms:
http://www.ddj.com/windows/184416337?pgno=11

Note that if you guarantee power of 2 dimensions you can get significant speed improvements.

羅雙樹 2024-08-19 20:57:54

作为我的问题和提供的答案的后续,让我总结以下内容:

  1. 我使用了 http://www.codeguru.com/cpp/gm/gdi/article.php/c3693/

  2. 它可以工作,并提供非常好的性能和流畅的显示。

  3. 其中存在一些错误,我需要修复并简化公式和
    在某些情况下代码。

  4. 我将检查 http://www.ddj.com/ 中提到的算法windows/184416337?pgno=11 看看它是否提供了一些值得调整的突破性性能。

  5. 我的实现需要使用大型源位图,因此我需要修改代码,这样我就不会每次都旋转整个位图,而只会旋转将在屏幕上显示的相关部分(否则性能将无法接受)。< /p>

阿维。

As follow up to my question and provided answer, let me summarize the following:

  1. I used the algorithm mentioned at http://www.codeguru.com/cpp/g-m/gdi/article.php/c3693/.

  2. It works and provide pretty good performance and smooth display.

  3. There were some bugs in it that I needed to fix as well as simplify the formulas and
    code in some cases.

  4. I will examine the algorithm mentioned at http://www.ddj.com/windows/184416337?pgno=11 to see if it provides some break through performance that worth adapting it.

  5. My implementation required using a large source bitmap, so I needed to modify the code so I will not rotate the whole bitmap each time but only the relevant portion that will be displayed at the screen (otherwise performance would be unacceptable).

Avi.

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