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Lua - 从用户那里获取命令行输入？

发布于 2024-08-12 08:17:18 字数 59 浏览 7 评论 0原文

在我的 lua 程序中，我想在继续操作之前停止并要求用户确认。我不知道如何停止并等待用户输入，该怎么办？

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顾挽 2024-08-19 08:17:18

local answer
repeat
   io.write("continue with this operation (y/n)? ")
   io.flush()
   answer=io.read()
until answer=="y" or answer=="n"

local answer
repeat
   io.write("continue with this operation (y/n)? ")
   io.flush()
   answer=io.read()
until answer=="y" or answer=="n"

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就此别过 2024-08-19 08:17:18

看一下 io 库，它默认将标准输入作为默认输入文件：

http://www.lua.org/pil/21.1.html

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手长情犹 2024-08-19 08:17:18

我曾经使用过这样的代码。我将以一种有效的方式输入：

io.write("continue with this operation (y/n)?")
answer=io.read()
if answer=="y" then
   --(put what you want it to do if you say y here)
elseif answer=="n" then
   --(put what you want to happen if you say n)
end

I've worked with code like this. I will type this in a way it will work:

io.write("continue with this operation (y/n)?")
answer=io.read()
if answer=="y" then
   --(put what you want it to do if you say y here)
elseif answer=="n" then
   --(put what you want to happen if you say n)
end

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反差帅 2024-08-19 08:17:18

我用：

     print("Continue (y/n)?")
re = io.read()
if re == "y" or "Y" then
    (Insert stuff here)
elseif re == "n" or "N" then
    print("Ok...")
end

I use:

     print("Continue (y/n)?")
re = io.read()
if re == "y" or "Y" then
    (Insert stuff here)
elseif re == "n" or "N" then
    print("Ok...")
end

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一身骄傲 2024-08-19 08:17:18

尝试使用以下代码

m=io.read()
如果 m==“是”那么
（在此处插入函数）
结束

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标点 2024-08-19 08:17:18

print("Continue (y/n)?")
re = io.read()
if re == "y" or "Y" then
    (Insert stuff here)
elseif re == "n" or "N" then
    print("Ok...")
end

从我完成的 lua 工作来看（不是很多），我想说的是，如果你使用 string.sub，同时使用大写和小写字母是多余的。

print("Continue? (y/n)")
local re = io.read()

--[[Can you get string.sub from a local var? 
If so, this works. I'm unfamiliar with io(game 
lua uses GUI elements and keypresses in place of the CLI.]]

if re.sub == "y" then
    --do stuff
if re.sub == "n" then
    --do other stuff
end

那应该有效。

print("Continue (y/n)?")
re = io.read()
if re == "y" or "Y" then
    (Insert stuff here)
elseif re == "n" or "N" then
    print("Ok...")
end

From the bit of lua that I've done (not a lot), I'm going to say that using both uppercase and lowercase letters is redundant if you use string.sub.

print("Continue? (y/n)")
local re = io.read()

--[[Can you get string.sub from a local var? 
If so, this works. I'm unfamiliar with io(game 
lua uses GUI elements and keypresses in place of the CLI.]]

if re.sub == "y" then
    --do stuff
if re.sub == "n" then
    --do other stuff
end

That should work.

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