如何在本地主机上启动 cxf 服务但在 wsdl 中返回外部地址？
我在apache后面使用cxf和jetty通过soap公开web服务。目标是在所有情况下在 http://localhost:9000 上启动 jetty 并拥有 apache 代理，但有自动生成的 wsdl 显示适合其运行环境的soap:address（例如 http://api.testing.example .com，http://api.uat.example.com，https://api.example.com)。似乎生成的 wsdl2java *Service 类接受 wsdl 的 URL，并且该 URL 必须充当开始的“位置”以及soap:address 中返回的字符串。这必须是可配置的，但并不明显，所以建议值得赞赏。
更清楚一点 - 我通过 Spring 将“WsdlURL”传递给 Service 类的构造函数（到目前为止仅 http:// /localhost:9000 有效）。我需要解决此问题的方法是在 cxf.cml、cxf-.xml、spring 或其他配置文件中进行配置更改，而不是在代码中更改，因为此参数将根据其所在的环境而更改部署。
I'm using cxf and jetty behind apache to expose a webservice via soap. The goal is to start jetty on http://localhost:9000 in all cases and have apache proxy to it, but have the autogenerated wsdl show a soap:address appropriate to the environment it's running in (eg http://api.testing.example.com, http://api.uat.example.com, https://api.example.com). It seems that the generated wsdl2java *Service class accepts a URL for the wsdl and that must serve as both the "location" to start at as well as the string returned in soap:address. This must be configurable, but it ain't obvious, so advice is appreciated.
A little more clarity - I'm passing in the "WsdlURL" to the constructor of the Service class via Spring (so far only http://localhost:9000 works). I need the solution to this problem to be a configuration change either in cxf.cml, cxf-.xml, spring or some other config file, rather than in the code, since this parameter will change based on the environment to which it is being deployed.
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jaxws:endpoint 配置有一个“publishedEndpointURL”，如果指定了地址，则使用该“publishedEndpointURL”来代替地址。知道 servlet 正确使用它，但在码头上不能 100% 确定。他们共享很多代码，因此它可能有效。
The jaxws:endpoint configuration thing has a "publishedEndpointURL" which is used instead of the address if it's specified. In know the servlet uses that properly, not 100% sure on the jetty. They share a lot of code so it MAY work.
尝试@WebService(wsdlLocation="http://yourdesiredlocation")。不确定它是否会起作用。
Try
@WebService(wsdlLocation="http://yourdesiredlocation"). Not sure if it will work.