如何解析 Perforce “pickle”二进制输出？

发布于 2024-08-11 06:41:00 字数 322 浏览 7 评论 0原文

Perforce 命令行有一个特殊的开关 -G，据说可以使用 python 的“pickle”序列化格式使其输出成为机器可读的。一般来说，情况确实如此吗？

例如，考虑 p4 -G diff -duw3的输出<文件2> <文件3>。据我所知，输出是一个序列：pickle、raw diff、pickle、raw diff、pickle、raw diff。它似乎不包含任何可以使人可靠地定位 pickle/diff 边界的分隔符。

我是否遗漏了某些内容，或者这种“机器可读”格式实际上不是机器可读的？如何在其输出中找到泡菜和原始差异之间的界限？

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动听の歌 2024-08-18 06:41:00

p4 -G 以编组格式（未腌制）输出其数据。

但你是对的 - p4 -G diff -duw3 也不会取消marshal，所以我猜那里有问题。

不过，p4 -G opening 解组效果很好。然而任何类型的 diff 都会失败。

以下是相关知识库文章：http://kb.perforce.com/ToolsScripts/PerforceUtilities/UsingP4G

#!/usr/bin/env python
import marshal
import subprocess

# proc = subprocess.Popen(["p4","-G","diff","-duw3","configure.ac","Makefile.am"],stdout=subprocess.PIPE)
proc = subprocess.Popen(["p4","-G","diff"],stdout=subprocess.PIPE)
# proc = subprocess.Popen(["p4","-G","opened"],stdout=subprocess.PIPE)
pipe = proc.stdout
output = []
try:
    while 1:
        record = marshal.load(pipe)
        output.append(record)
except EOFError:
    pass
pipe.close()
proc.wait()

# print list of dictionary records
c = 0
for dict in output:
    c = c + 1
    print "\n--%d--" % c
    for key in dict.keys():
        print "%s: %s" % ( key, dict[key] )

p4 -G outputs its data in marshaled form not pickled.

But you are right - p4 -G diff -duw3 also won't unmarshal, so I guess there is a problem there.

p4 -G opened unmarshals fine though. However any kind of diff fails.

Here is a relevant knowledge base article: http://kb.perforce.com/ToolsScripts/PerforceUtilities/UsingP4G

#!/usr/bin/env python
import marshal
import subprocess

# proc = subprocess.Popen(["p4","-G","diff","-duw3","configure.ac","Makefile.am"],stdout=subprocess.PIPE)
proc = subprocess.Popen(["p4","-G","diff"],stdout=subprocess.PIPE)
# proc = subprocess.Popen(["p4","-G","opened"],stdout=subprocess.PIPE)
pipe = proc.stdout
output = []
try:
    while 1:
        record = marshal.load(pipe)
        output.append(record)
except EOFError:
    pass
pipe.close()
proc.wait()

# print list of dictionary records
c = 0
for dict in output:
    c = c + 1
    print "\n--%d--" % c
    for key in dict.keys():
        print "%s: %s" % ( key, dict[key] )

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