ALSA 的 pcm_min.c 示例中的警告/错误。可能的问题?
当我编译 ALSA 的 pcm_min.c 示例
gcc -Wall -lasound pcm_min.c -o pcm_min
一切都很好,但是运行它,我得到了预期的白噪声,但我也得到了这个警告/错误:
Short write (expected 16384, wrote 7616)
来自最后一个 if 语句。
#include <alsa/asoundlib.h>
static char *device = "default"; /* playback device */
snd_output_t *output = NULL;
unsigned char buffer[16*1024]; /* some random data */
int main(void)
{
int err;
unsigned int i;
snd_pcm_t *handle;
snd_pcm_sframes_t frames;
for (i = 0; i < sizeof(buffer); i++)
buffer[i] = random() & 0xff;
if ((err = snd_pcm_open(&handle, device, SND_PCM_STREAM_PLAYBACK, 0)) < 0) {
printf("Playback open error: %s\n", snd_strerror(err));
exit(EXIT_FAILURE);
}
if ((err = snd_pcm_set_params(handle,
SND_PCM_FORMAT_U8,
SND_PCM_ACCESS_RW_INTERLEAVED,
1,
48000,
1,
500000)) < 0) { /* 0.5sec */
printf("Playback open error: %s\n", snd_strerror(err));
exit(EXIT_FAILURE);
}
for (i = 0; i < 16; i++) {
frames = snd_pcm_writei(handle, buffer, sizeof(buffer));
if (frames < 0)
frames = snd_pcm_recover(handle, frames, 0);
if (frames < 0) {
printf("snd_pcm_writei failed: %s\n", snd_strerror(err));
break;
}
if (frames > 0 && frames < (long)sizeof(buffer))
printf("Short write (expected %li, wrote %li)\n", (long)sizeof(buffer), frames);
}
snd_pcm_close(handle);
return 0;
}
有人能明白为什么会出现此警告/错误吗?
拥抱, 路易丝
When I compile ALSA's pcm_min.c example with
gcc -Wall -lasound pcm_min.c -o pcm_min
Everything is fine, but running it, I get the white noise as expected, but I also get this warning/error:
Short write (expected 16384, wrote 7616)
Which comes from the last if-statement.
#include <alsa/asoundlib.h>
static char *device = "default"; /* playback device */
snd_output_t *output = NULL;
unsigned char buffer[16*1024]; /* some random data */
int main(void)
{
int err;
unsigned int i;
snd_pcm_t *handle;
snd_pcm_sframes_t frames;
for (i = 0; i < sizeof(buffer); i++)
buffer[i] = random() & 0xff;
if ((err = snd_pcm_open(&handle, device, SND_PCM_STREAM_PLAYBACK, 0)) < 0) {
printf("Playback open error: %s\n", snd_strerror(err));
exit(EXIT_FAILURE);
}
if ((err = snd_pcm_set_params(handle,
SND_PCM_FORMAT_U8,
SND_PCM_ACCESS_RW_INTERLEAVED,
1,
48000,
1,
500000)) < 0) { /* 0.5sec */
printf("Playback open error: %s\n", snd_strerror(err));
exit(EXIT_FAILURE);
}
for (i = 0; i < 16; i++) {
frames = snd_pcm_writei(handle, buffer, sizeof(buffer));
if (frames < 0)
frames = snd_pcm_recover(handle, frames, 0);
if (frames < 0) {
printf("snd_pcm_writei failed: %s\n", snd_strerror(err));
break;
}
if (frames > 0 && frames < (long)sizeof(buffer))
printf("Short write (expected %li, wrote %li)\n", (long)sizeof(buffer), frames);
}
snd_pcm_close(handle);
return 0;
}
Can someone see why this warning/error occur?
Hugs,
Louise
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评论(2)
当收到信号或欠载时,
snd_pcm_writei()
函数返回的值可能小于sizeof(buffer)
。就您而言,您似乎正在混合字节和帧。调用的最后一个参数是缓冲区中的帧数。由于您正在传递缓冲区中的字节数,因此您会看到欠载。The
snd_pcm_writei()
function might return less thansizeof(buffer)
when there's either a signal received or an underrun. In your case, it seems that you're mixing bytes and frames. The last parameter of the call is the number of frames that you have in your buffer. Since you're passing the number of bytes in your buffer instead, you're seeing an underrun.我对这个例子也有一些问题。我对其进行了一些修改,现在它可以工作了。
I was also having some problems with this example. I modified it a bit and now it works.