Many_to_many、sti 和 will 分页

Question

我有以下代码

class Category < ActiveRecord::Base
  has_many :categorizations
  has_many :posts, :through => :categorizations
end

class Post < ActiveRecord::Base
  has_many :categorizations
  has_many :categories, :through => :categorizations
end

class Categorization < ActiveRecord::Base
  belongs_to :post
  belongs_to :category
end

class NewsArticle < Post
end

，看起来不错。我试图从类别中获取所有 NewsArticle

@news_articles = NewsArticle.paginate_by_category_id params[:category],
  :page => params[:page], :per_page => 10,
  :order => 'posts.created_at DESC'

，我知道

 NoMethodError in News articlesController#category

undefined method `find_all_by_category' for #<Class:0x103cb05d0>

我能做些什么来解决这个问题？

Answer 1

怎么样：

@news_articles = NewsArticle.paginate(:conditions => { :category_id => params[:category_id].to_i }, :page => params[:page], :per_page => 10, :order => 'posts.created_at DESC')

您是否将类别 ID 作为 params[:category] 或 params[:category_id] 传递？如果您不确定可以在视图中debug(params)。

Answer 2

我将添加命名范围并将其与分页一起使用：

class Post < ActiveRecord::Base
  ..
  named_scope :newest, :order => 'posts.created_at DESC'
  named_scope :by_category, lambda { |category_id| { 
    :joins => :categories,
    :conditions => ['categories.category_id = ?', category_id]
  } }
end

@news_articles = NewsArticle.newest.by_category(params[:category]).paginate(
  :page => params[:page], :per_page => 10
  )