使用 python 获取一些 ofx 数据

发布于 2024-08-09 03:08:55 字数 3414 浏览 2 评论 0原文

我试图使用 http://www.jongsma.org/gc/scripts /ofx-ba.py 从 wachovia 获取我的银行帐户信息。运气不好，我决定尝试使用这个示例手动构造一些请求数据

所以，我有这个文件想要用作请求数据。让我们称之为 req.ofxsgml：

FXHEADER:100
DATA:OFXSGML
VERSION:102
SECURITY:NONE
ENCODING:USASCII
CHARSET:1252
COMPRESSION:NONE
OLDFILEUID:NONE
NEWFILEUID:NONE

<OFX>
  <SIGNONMSGSRQV1>
    <SONRQ>
      <DTCLIENT>20071015021529.000[-8:PST]
      <USERID>TheNameIuseForOnlineBanking
      <USERPASS>MySecretPassword
      <LANGUAGE>ENG
      <FI>
        <ORG>Wachovia
        <FID>4309
      </FI>
      <APPID>Money
      <APPVER>1700
    </SONRQ>
  </SIGNONMSGSRQV1>
  <BANKMSGSRQV1>
    <STMTTRNRQ>
      <TRNUID>438BD6F4-2106-4C88-8DE5-7625915A2FC0
      <STMTRQ>
        <BANKACCTFROM>
          <BANKID>061000227
          <ACCTID>101555555555
          <ACCTTYPE>CHECKING
        </BANKACCTFROM>
        <INCTRAN>
          <INCLUDE>Y
        </INCTRAN>
      </STMTRQ>
    </STMTTRNRQ>
  </BANKMSGSRQV1>
</OFX>

然后，在 python 中，我尝试：

>>> import urllib2
>>> query = open('req.ofxsgml').read()
>>> request = urllib2.Request('https://pfmpw.wachovia.com/cgi-forte/fortecgi?servicename=ofx&amp;pagename=PFM',
                              query,
                              { "Content-type": "application/x-ofx",
                                "Accept": "*/*, application/x-ofx"
                              })
>>> f = urllib2.urlopen(request)

这个命令给我一个 500 和这个回溯< /a>.我想知道我的要求有什么问题。

访问没有数据且不关心标头的 url，

>>> f = urllib2.urlopen('https://pfmpw.wachovia.com/cgi-forte/fortecgi?servicename=ofx&amp;pagename=PFM')

会产生与访问那个 url，

HTTPError: HTTP Error 403: <BODY><H1>Request not allowed</H1></BODY>.

这是非常明显的，但只是一个观察。关于这个主题的一切似乎都已经过时了。希望写一个简单的python ofx模块来开源。也许已经开发出了一些我还没有找到的东西？

编辑 - 如果我对上述信息进行平面映射：

d = {'ACCTID': '10555555',
 'ACCTTYPE': 'CHECKING',
 'APPID': 'Money',
 'APPVER': '1700',
 'BANKID': '061000227',
 'DTCLIENT': '20071015021529.000[-8:PST]',
 'FID': '4309',
 'INCLUDE': 'Y',
 'LANGUAGE': 'ENG',
 'ORG': 'Wachovia',
 'TRNUID': 'I18BD6F4-2006-4C88-8DE5-7625915A2FC0',
 'USERID': 'm48m40',
 'USERPASS': '12397'}

然后对其进行 urlencode 并将其作为数据发出请求

query=urllib.urlencode(d)
request = urllib2.Request('https://pfmpw.wachovia.com/cgi-forte/fortecgi?servicename=ofx&amp;pagename=PFM',
                              query,
                              { "Content-type": "application/x-ofx",
                                "Accept": "*/*, application/x-ofx"
                              })

f = urllib2.urlopen(request)
HTTP Error 403: <BODY><H1>Request not allowed</H1></BODY>

原文

I was trying to use http://www.jongsma.org/gc/scripts/ofx-ba.py to grab my bank account information from wachovia. Having no luck, I decided that I would just try to manually construct some request data using this example

So, I have this file that I want to use as the request data. Let's call it req.ofxsgml:

FXHEADER:100
DATA:OFXSGML
VERSION:102
SECURITY:NONE
ENCODING:USASCII
CHARSET:1252
COMPRESSION:NONE
OLDFILEUID:NONE
NEWFILEUID:NONE

<OFX>
  <SIGNONMSGSRQV1>
    <SONRQ>
      <DTCLIENT>20071015021529.000[-8:PST]
      <USERID>TheNameIuseForOnlineBanking
      <USERPASS>MySecretPassword
      <LANGUAGE>ENG
      <FI>
        <ORG>Wachovia
        <FID>4309
      </FI>
      <APPID>Money
      <APPVER>1700
    </SONRQ>
  </SIGNONMSGSRQV1>
  <BANKMSGSRQV1>
    <STMTTRNRQ>
      <TRNUID>438BD6F4-2106-4C88-8DE5-7625915A2FC0
      <STMTRQ>
        <BANKACCTFROM>
          <BANKID>061000227
          <ACCTID>101555555555
          <ACCTTYPE>CHECKING
        </BANKACCTFROM>
        <INCTRAN>
          <INCLUDE>Y
        </INCTRAN>
      </STMTRQ>
    </STMTTRNRQ>
  </BANKMSGSRQV1>
</OFX>

Then, in python, I try:

>>> import urllib2
>>> query = open('req.ofxsgml').read()
>>> request = urllib2.Request('https://pfmpw.wachovia.com/cgi-forte/fortecgi?servicename=ofx&pagename=PFM',
                              query,
                              { "Content-type": "application/x-ofx",
                                "Accept": "*/*, application/x-ofx"
                              })
>>> f = urllib2.urlopen(request)

This command gives me a 500 and this traceback. I wonder what is wrong with my request.

Visiting the url with no data and no concern for headers,

>>> f = urllib2.urlopen('https://pfmpw.wachovia.com/cgi-forte/fortecgi?servicename=ofx&pagename=PFM')

yields the same thing as visiting that url directly,

HTTPError: HTTP Error 403: <BODY><H1>Request not allowed</H1></BODY>.

This is pretty obvious but just an observation. Everything on the subject seems to be pretty outdated. Hoping to write a simple python ofx module to open source. Maybe there is already something developed that I have not managed to find?

EDIT -
If I make a flat mapping of the above information:

d = {'ACCTID': '10555555',
 'ACCTTYPE': 'CHECKING',
 'APPID': 'Money',
 'APPVER': '1700',
 'BANKID': '061000227',
 'DTCLIENT': '20071015021529.000[-8:PST]',
 'FID': '4309',
 'INCLUDE': 'Y',
 'LANGUAGE': 'ENG',
 'ORG': 'Wachovia',
 'TRNUID': 'I18BD6F4-2006-4C88-8DE5-7625915A2FC0',
 'USERID': 'm48m40',
 'USERPASS': '12397'}

and then urlencode it and make the request with that as the data

query=urllib.urlencode(d)
request = urllib2.Request('https://pfmpw.wachovia.com/cgi-forte/fortecgi?servicename=ofx&pagename=PFM',
                              query,
                              { "Content-type": "application/x-ofx",
                                "Accept": "*/*, application/x-ofx"
                              })

f = urllib2.urlopen(request)
HTTP Error 403: <BODY><H1>Request not allowed</H1></BODY>

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