如何读取具有透明度的java BufferedImage中的像素颜色

发布于 2024-08-08 15:35:42 字数 471 浏览 8 评论 0原文

我正在读取 BufferedImage 中的像素颜色，如下所示：

.....
InputStream is = new BufferedInputStream(conn.getInputStream());
BufferedImage image = ImageIO.read(is);

int color = image.getRGB(x, y);

int  red = (colour & 0x00ff0000) >> 16;
int  green = (colour & 0x0000ff00) >> 8;
int  blue = colour & 0x000000ff;

现在除了具有透明度的 png 之外，这一切都很好。我发现如果 x,y 指的是没有颜色的透明像素，我仍然读取颜色，通常与图像中其他地方使用的颜色相同。

如何检测像素实际上是透明的而不是彩色的？

谢谢

原文

I am reading pixel color in a BufferedImage as follows:

.....
InputStream is = new BufferedInputStream(conn.getInputStream());
BufferedImage image = ImageIO.read(is);

int color = image.getRGB(x, y);

int  red = (colour & 0x00ff0000) >> 16;
int  green = (colour & 0x0000ff00) >> 8;
int  blue = colour & 0x000000ff;

Now this works fine except for png's with transparency. I find that if x,y refer to a transparent pixel with no color, i still read a color, generally the same color as used elsewhere in the image.

How do I detect that the pixel is actually transparent and not colored?

Thanks

分享到QQ

分享到微博