PHP选择一方死了有吗？

发布于 2024-08-08 04:47:32 字数 1398 浏览 3 评论 0原文

我的代码的 php 部分没有执行正确的操作当用户提交他/她的号码时，例如，如果用户提交5，我希望rand函数随机输出5作为所选的号码；但是，我的代码有时有效，有时则无效。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">


<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" />
<title>
choose a die number
</title>
</head>
<center>
<body>
<h1>Choose a die number</h1>
<form method = "post" action="choosedie.php"/>
<!--If the user selects a number of sides the die is suppose to have
rand should go through and pick the number randomly, and echo out the 
number that was entered by the user-->

Please choose how many sides a die should have from 1 through 6:
<br/>
<input type = "text" name = "roll"/>
<?php


//Roll a random dice from 1 through 6:
$roll = rand(1,6);
// Add random variable to do comparison on.

有没有办法让我在这里比较 rand，而不必创建另一个变量？

$random  = rand(1,6);

// If $roll is equal to $random echo the output out to the user.
If ($roll == $random)
{
echo "<br/>Here is the random $roll with the appropriate maximum value $random\n";

如果用户选择 5，我希望它回显 5，但我得到不同的值？

}


?>


</body>
</center>
</html>

原文

The php section of my code is not doing the correct operations
when the user submits his/her number, for example, if the user submits 5, I want the rand function to randomly output 5 as the number selected; however, my code sometimes works and at other times does not work.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">


<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" />
<title>
choose a die number
</title>
</head>
<center>
<body>
<h1>Choose a die number</h1>
<form method = "post" action="choosedie.php"/>
<!--If the user selects a number of sides the die is suppose to have
rand should go through and pick the number randomly, and echo out the 
number that was entered by the user-->

Please choose how many sides a die should have from 1 through 6:
<br/>
<input type = "text" name = "roll"/>
<?php


//Roll a random dice from 1 through 6:
$roll = rand(1,6);
// Add random variable to do comparison on.

Is there a way for me to just compare rand here, without having to create another variable?

$random  = rand(1,6);

// If $roll is equal to $random echo the output out to the user.
If ($roll == $random)
{
echo "<br/>Here is the random $roll with the appropriate maximum value $random\n";

If the user selects 5, I want this to echo out 5, but I am getting different values?

}


?>


</body>
</center>
</html>

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靖瑶 2024-08-15 04:47:32

由于 rand(n,m) 返回一个整数值，您应该能够这样做：

if(rand(1,6) == $guess){
    echo "Congratulations - your guess of $guess was right!";
}
else{
    echo "No dice - better luck next time.";
}

Since rand(n,m) returns an integer value, you should be able to do thusly:

if(rand(1,6) == $guess){
    echo "Congratulations - your guess of $guess was right!";
}
else{
    echo "No dice - better luck next time.";
}

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别再吹冷风 2024-08-15 04:47:32

我认为你在这里想做的是要求用户输入骰子有多少面，然后输出该值是多少？这个问题没有多大意义......但如果上面是您想要做的，那么这应该可行：

choosedie.php

<h1>Choose a die number</h1>
<form method = "post" action="choosedie.php"/> 
Please choose how many sides a die should have from 1 through 6:
<br/>
<input type="text" name="roll"/>
<input type="submit" value="Submit" />
</form>

<?php
if (isset($_POST["roll"])) {
  $roll = rand(1, $_POST["roll"]);
  printf("A %s was rolled, with a maximum roll of %s", $roll, $_POST["roll"]);
}
?>

这将允许用户输入的数量骰子有面，然后打印出滚动的内容以及面数。

I think what you're trying to do here is ask the user to input how many sides the die has and then output what the value is? The question doesn't make a lot of sense... but if the above is what you're trying to do, this should work:

choosedie.php

<h1>Choose a die number</h1>
<form method = "post" action="choosedie.php"/> 
Please choose how many sides a die should have from 1 through 6:
<br/>
<input type="text" name="roll"/>
<input type="submit" value="Submit" />
</form>

<?php
if (isset($_POST["roll"])) {
  $roll = rand(1, $_POST["roll"]);
  printf("A %s was rolled, with a maximum roll of %s", $roll, $_POST["roll"]);
}
?>

This will allow the user to input the number of sides a die has, and then print out what was rolled along with the number of sides.

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铁轨上的流浪者 2024-08-15 04:47:32

我不确定你想做什么。每次加载此页面时，它都会选择两个随机数，$random 和 $roll，如果它们相等，则打印它们。

如果您想获取用户输入，则需要使用 $_POST。

$users_dice_roll = $_POST["roll"];
$random_dice_roll = rand(1,6);
if($random_dice_roll == $users_dice_roll){
    echo "You rolled: $users_guess";
}

另外，你不需要提交按钮吗？

I'm not sure what you're trying to do. Each time this page is loaded, it will pick two random numbers, $random and $roll, and if they are equal, print them.

If you want to get the users input, you'll need to use $_POST.

$users_dice_roll = $_POST["roll"];
$random_dice_roll = rand(1,6);
if($random_dice_roll == $users_dice_roll){
    echo "You rolled: $users_guess";
}

Also, don't you need a submit button?

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不再见

真是无聊啊

樱娆

浅语花开

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绻影浮沉

友情链接

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。