弹出窗口与同一域的另一个窗口之间的跨窗口js交互

发布于 2024-08-07 14:34:04 字数 499 浏览 1 评论 0原文

我正在尝试从 example.com 的窗口 a 打开一个弹出窗口。然后关闭窗口 a 并在同一域 (example.com) 中打开另一个窗口 b。是否可以从窗口b访问窗口a的DOM以及如何访问？

打开弹出窗口，

window.open('http://example.com/blah', 'somename', settings..),

通过使用不同的 url（如下所示）从窗口 b 执行相同的操作，可以从窗口 a

window.open("http://example.com/blah2", "somename" ...)

这似乎表明窗口是通过窗口名称访问的。但我找不到任何方法来访问带有或不带有窗口名称的弹出窗口的 DOM。我该怎么做？

原文

I'm trying to open a popup from window a at example.com. then close window a and open another window b at the same domain (example.com). Is it possible to access the DOM of window a from window b and how?

The popup is opened from window a by

window.open('http://example.com/blah', 'somename', settings..),

Executing the same from window b with a different url (shown below) works

window.open("http://example.com/blah2", "somename" ...)

This seems to suggest windows are accessed by window name. But I could not find any way to access to DOM of the popup with or without the window's name. How would I do this?

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┼── 2024-08-14 14:34:04

尝试类似的东西

var newWind = window.open('http://example.com/blah', 'somename',settings);
if (newWind.opener == null) {
    newWind.opener = window;
}
// here you can access DOM of new window
var newDoc = newWind.document;

Try something like

var newWind = window.open('http://example.com/blah', 'somename',settings);
if (newWind.opener == null) {
    newWind.opener = window;
}
// here you can access DOM of new window
var newDoc = newWind.document;

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