SQL DELETE 在 PHPmyAdmin 中失败

发布于 2024-08-06 19:38:13 字数 374 浏览 3 评论 0原文

SQL DELETE 在 PHPmyAdmin 中失败。无法弄清楚为什么；是因为 LEFT OUTER JOIN 吗？

SELECT * 
  FROM `User` 
LEFT OUTER JOIN `freshersdata` ON `User`.`username`=`freshersdata`.`username` 
 WHERE (`freshersdata`.`username` IS null) 
   AND (`User`.`Persistent`!=1)

此 SQL 查询失败并显示 (#1064 - You had an error in your SQL syntax;) 消息，但使用 SELECT 而不是删除可以完美工作，这是为什么？

原文

SQL DELETE falling over in PHPmyAdmin. Can't work out why; is it because of LEFT OUTER JOIN?

SELECT * 
  FROM `User` 
LEFT OUTER JOIN `freshersdata` ON `User`.`username`=`freshersdata`.`username` 
 WHERE (`freshersdata`.`username` IS null) 
   AND (`User`.`Persistent`!=1)

This SQL query is falling over with ( #1064 - You have an error in your SQL syntax; ) message but works perfecly with a SELECT instead of a delete, why is this?

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心是晴朗的。 2024-08-13 19:38:13

您必须指定要从哪个表中删除：

例如从用户中：

DELETE User.* 
  FROM User 
LEFT OUTER JOIN freshersdata ON User.username=freshersdata.username 
 WHERE (freshersdata.username IS null) AND (User.Persistent!=1)

You have to specify from which table you want to delete:

For example from User:

DELETE User.* 
  FROM User 
LEFT OUTER JOIN freshersdata ON User.username=freshersdata.username 
 WHERE (freshersdata.username IS null) AND (User.Persistent!=1)

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携余温的黄昏 2024-08-13 19:38:13

DELETE FROM User 
LEFT OUTER JOIN 
   freshersdata ON User.username=freshersdata.username  
WHERE (freshersdata.username IS null) AND (User.Persistent!=1)

DELETE FROM User 
LEFT OUTER JOIN 
   freshersdata ON User.username=freshersdata.username  
WHERE (freshersdata.username IS null) AND (User.Persistent!=1)

回复收藏 0 原文

~没有更多了~