PROGRESS 数据库条件连接的 SQL 命令

发布于 2024-08-06 19:28:23 字数 379 浏览 5 评论 0原文

请耐心等待 SQL 新手 - 我正在尝试编写一个带有 PROGRESS 数据库连接的 SQL 命令。然后我想仅从连接中选择第一个匹配的记录。我想使用 LIMIT 但 PROGRESS 不支持。我认为 MIN 或 TOP 也可以工作，但语法有问题。像这样的东西？ -

SELECT table1.field 1, table2.field 2
FROM table2
INNER JOIN table2
ON table1.field3=table2.field3
WHERE table1.field4 in (SELECT min(table1.field4) FROM table1)

但看来我不能在那里使用 MIN ，因为不能在那里进行聚合。任何帮助都会是巨大的。

原文

Please bear with me new to SQL- I am trying to write an SQL command with a join in a PROGRESS db. I would like to then select only the first matching record from the join. I thought to use LIMIT but PROGRESS does not support that. MIN or TOP would also work I think but having trouble with the syntax.
Something like this?-

SELECT table1.field 1, table2.field 2
FROM table2
INNER JOIN table2
ON table1.field3=table2.field3
WHERE table1.field4 in (SELECT min(table1.field4) FROM table1)

BUt it appears I can't use MIN there as saying can't do an aggregate there.
Any help would be huge.

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春庭雪 2024-08-13 19:28:23

尝试：

SELECT
    t1.field1, t2.field2
    FROM table1            t1
        INNER JOIN table2  t2 ON t1.field3=t2.field3
    WHERE t1.field4=(SELECT min(t.field4) FROM table1 t WHERE t1.field4=t.field4)

try:

SELECT
    t1.field1, t2.field2
    FROM table1            t1
        INNER JOIN table2  t2 ON t1.field3=t2.field3
    WHERE t1.field4=(SELECT min(t.field4) FROM table1 t WHERE t1.field4=t.field4)

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