指向抽象模板基类的指针？

发布于 2024-08-06 17:01:15 字数 848 浏览 4 评论 0原文

我无法弄清楚这一点。我需要有一个抽象模板基类，它如下：


template <class T> class Dendrite
{
    public:
        Dendrite()
        {
        }

        virtual ~Dendrite()
        {
        }

        virtual void Get(std::vector<T> &o) = 0;

    protected:
        std::vector<T> _data;
};

现在，我从中得出它指定了 Dendrite 的确切用法。

现在问题来了。

如何创建指向没有特定类型的基类的指针向量我想通过稍后将元素推送到它来指定？比如：


class Foo
{
    public:
        ...

    private:
        std::vector<Dendrite *> _inputs; //!< Unfortunately, this doesn't work...

        //! Now I could later on push elements to this vector like
        //!
        //! _inputs.push_back(new DeriveFromDendrite<double>()) and
        //! _inputs.push_back(new DeriveFromDendrite<int>()).
};

这可能吗，还是我在这里遗漏了一些非常基本的东西？

原文

I cannot figure this out. I need to have an abstract template base class, which
is the following:


template <class T> class Dendrite
{
    public:
        Dendrite()
        {
        }

        virtual ~Dendrite()
        {
        }

        virtual void Get(std::vector<T> &o) = 0;

    protected:
        std::vector<T> _data;
};

Now, I derive from this which specifies exact usage of Dendrite.

Now the problem.

How do I create a vector of pointers to the base-class with no specific type, which
I want to specify by pushing elements to it later? Something like:


class Foo
{
    public:
        ...

    private:
        std::vector<Dendrite *> _inputs; //!< Unfortunately, this doesn't work...

        //! Now I could later on push elements to this vector like
        //!
        //! _inputs.push_back(new DeriveFromDendrite<double>()) and
        //! _inputs.push_back(new DeriveFromDendrite<int>()).
};

Is this possible or am I missing something very basic here?

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似最初 2024-08-13 17:01:15

通常，这是通过从接口类 IE 继承的模板来完成的：

template <class T> class Dendrite : public IDendrite
{
        public:
                Dendrite()
                {
                }

                virtual ~Dendrite()
                {
                }

                void Get(std::vector<T> &o) = 0;

        protected:
                std::vector<T> _data;
};

然后您的 IDendrite 类可以存储为指针：

std::vector<IDendrite*> m_dendriteVec;

但是，在您的情况下，您将模板参数作为接口的一部分。您可能还需要将其包装起来。

class IVectorParam
{
}

template <class T>
class CVectorParam : public IVectorParam
{
    std::vector<T> m_vect;
}

给你

class IDendrite
{
   ...
public:
   virtual ~IDendrite()
   virtual void Get(IVectorParam*) = 0; 
}

template <class T> class Dendrite : public IDendrite
{
  ...
  // my get has to downcast to o CVectorParam<T>
  virtual void Get(IVectorParam*);
};

Typically this is done by your template inheriting from an interface class, IE:

template <class T> class Dendrite : public IDendrite
{
        public:
                Dendrite()
                {
                }

                virtual ~Dendrite()
                {
                }

                void Get(std::vector<T> &o) = 0;

        protected:
                std::vector<T> _data;
};

and then you're IDendrite class could be stored as pointers:

std::vector<IDendrite*> m_dendriteVec;

However, in your situation, you are taking the template parameter as part of your interface. You may also need to wrap this also.

class IVectorParam
{
}

template <class T>
class CVectorParam : public IVectorParam
{
    std::vector<T> m_vect;
}

giving you

class IDendrite
{
   ...
public:
   virtual ~IDendrite()
   virtual void Get(IVectorParam*) = 0; 
}

template <class T> class Dendrite : public IDendrite
{
  ...
  // my get has to downcast to o CVectorParam<T>
  virtual void Get(IVectorParam*);
};

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