英特尔 Fortran 编译器“-并行”不工作
我有一个运行良好的串行 Fortran 代码。一旦我使用 ifort -parallel 编译相同的代码并运行它，它就会给出错误的结果和溢出。我希望通过“-parallel”标志，英特尔编译器能够选择可以安全并行化的循环，并且我应该得到与串行代码完全相同的结果，但这并没有发生。更奇怪的行为是，我继续使用 !DEC$ NOPARALLEL 关闭代码中的所有 do 循环并行化，使用 ifort -parallel 编译代码以确保没有循环并行化然后运行。令人惊讶的是，我得到了相同的错误结果和溢出，尽管后一个操作应该完全等同于串行代码。
有没有人能够解释这种行为，或者这只是英特尔编译器的缺陷。
问候。
I have a serial Fortran code that works fine. Once I compile the same code using ifort -parallel and run it, it gives wrong results and overflow. I would expect that with "-parallel" flag, the Intel compiler is capable of selecting the loops that are safe to parallelize and I should get the exact same results as for the serial code, which did not happen. The even more strange behaviour is that I went ahead and closed all the do loops parallelization in my code using !DEC$ NOPARALLEL, compiled the code using ifort -parallel to make sure that non of the loops was parallelized and then run. Surprisingly, I got the same wrong results and overflow, although the latter action should be exactly equivalent to a serial code.
Is there any one capable of explaining this behaviour or is it just an Intel compiler deficiency.
Greetings.
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很抱歉这么说，但这不太可能是英特尔编译器的问题，它是一个非常好的编译器（不，我不为英特尔工作！但我确实使用他们的编译器）。
是的，我有能力解释这种行为，但是如果没有看到你的程序，我建议的任何内容都会是错误的。
Sorry to say this, but it's unlikely to be an Intel compiler problem it's a pretty good compiler (no, I don't work for Intel ! but I do use their compilers).
Yes I am capable of explaining this sort of behaviour, but without sight of your program anything I suggest will be wrong.
英特尔 Fortran 论坛上给出了相同问题的答案：http://software .intel.com/en-us/forums/topic/269743
编辑：我修改了链接，因为正如评论中所述，原始链接现已失效。
Answers were given to this identical question on the Intel Fortran Forum: http://software.intel.com/en-us/forums/topic/269743
EDIT: I revised the link, since as stated in the comment, the original link is now dead.