“print expr”的语法错误无效？

发布于 2024-08-05 19:23:04 字数 1209 浏览 3 评论 0原文

import os

import sys, urllib2, urllib

import re

import time

from threading import Thread

class testit(Thread):

    def _init_ (self):

        Thread.__init__(self)

    def run(self):

        url = 'http://games.espnstar.asia/the-greatest-odi/post_brackets.php'

        data = urllib.urlencode([('id',"btn_13_9_13"), ('matchNo',"13")])

        req = urllib2.Request(url)

        fd = urllib2.urlopen(req, data)

        """while 1:

        data = fd.read(1024)

        if not len(data):

        break

        sys.stdout.write(data)"""

        fd.close();

        url2 = 'http://games.espnstar.asia/the-greatest-odi/post_perc.php'

        data2 = urllib.urlencode([('id',"btn_13_9_13"), ('matchNo',"13")])

        req2 = urllib2.Request(url2)

        fd2 = urllib2.urlopen(req2, data2)

        while 1:

            data2 = fd2.read(1024)

        if not len(data2):

            break

        sys.stdout.write(data2)

        fd2.close()

        print time.ctime()

        print " ending thread\n"

i=-1

while i<0:

current = testit()

time.sleep(0.001)

current.start()

我收到一条错误，指出该行的语法无效：

print time.ctime()

请帮助我。

原文

import os

import sys, urllib2, urllib

import re

import time

from threading import Thread

class testit(Thread):

    def _init_ (self):

        Thread.__init__(self)

    def run(self):

        url = 'http://games.espnstar.asia/the-greatest-odi/post_brackets.php'

        data = urllib.urlencode([('id',"btn_13_9_13"), ('matchNo',"13")])

        req = urllib2.Request(url)

        fd = urllib2.urlopen(req, data)

        """while 1:

        data = fd.read(1024)

        if not len(data):

        break

        sys.stdout.write(data)"""

        fd.close();

        url2 = 'http://games.espnstar.asia/the-greatest-odi/post_perc.php'

        data2 = urllib.urlencode([('id',"btn_13_9_13"), ('matchNo',"13")])

        req2 = urllib2.Request(url2)

        fd2 = urllib2.urlopen(req2, data2)

        while 1:

            data2 = fd2.read(1024)

        if not len(data2):

            break

        sys.stdout.write(data2)

        fd2.close()

        print time.ctime()

        print " ending thread\n"

i=-1

while i<0:

current = testit()

time.sleep(0.001)

current.start()

I'm getting an error stating invalid syntax for the line:

print time.ctime()

Please help me out.

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被翻牌 2024-08-12 19:23:04

这是因为（至少在 Python 3.0 中），print 是一个函数。

使用：

print (time.ctime())

应该没问题。

This is because (in Python 3.0 onwards at least), print is a function.

Use:

print (time.ctime())

and it should be fine.

回复收藏 0 原文

┾廆蒐ゝ 2024-08-12 19:23:04

来自此页面：

ctime(...)
ctime（秒）->字符串
将纪元以来的时间（以秒为单位）转换为本地时间的字符串。
这相当于 asctime(localtime(seconds))。

ctime 需要一个参数，但您没有给它一个参数。如果您想获取当前时间，请尝试使用 time.time()。或者，如果您尝试将当前时间（以秒为单位）转换为本地时间的字符串，您应该尝试以下操作：

time.ctime(time.time())

From this page:

ctime(...)
ctime(seconds) -> string
Convert a time in seconds since the Epoch to a string in local time.
This is equivalent to asctime(localtime(seconds)).

ctime requires an argument and you aren't giving it one. If you're trying to get the current time, try time.time() instead. Or, if you're trying to convert the current time in seconds to a string in local time, you should try this: