多余的空
<?php
$salaries = array(1000,1500,2000,2500,3000,4000,5000,6000,7000,9000,12000,18000,30000);
$str = '';
foreach($salaries as $salary)
{
$str .= "<option value=\"$salary\">$salary+</option>";
}
function populateSalary()
{
$salaries = array(1000,1500,2000,2500,3000,4000,5000,6000,7000,9000,12000,18000,30000);
$str = '';
foreach($salaries as $salary)
{
$str .= "<option value=\"$salary\">$salary+</option>";
}
return $str;
}
?>
<select id="salaryExpect" name="salaryExpect">
<option value="-1">--<option>
<?php echo populateSalary(); ?>
</select>
看到了吗？没有 ，但输出中却有很奇怪的内容。
<?php
$salaries = array(1000,1500,2000,2500,3000,4000,5000,6000,7000,9000,12000,18000,30000);
$str = '';
foreach($salaries as $salary)
{
$str .= "<option value=\"$salary\">$salary+</option>";
}
function populateSalary()
{
$salaries = array(1000,1500,2000,2500,3000,4000,5000,6000,7000,9000,12000,18000,30000);
$str = '';
foreach($salaries as $salary)
{
$str .= "<option value=\"$salary\">$salary+</option>";
}
return $str;
}
?>
<select id="salaryExpect" name="salaryExpect">
<option value="-1">--<option>
<?php echo populateSalary(); ?>
</select>
See?There is no such empty option as <option> </option> in the code,but strange enough there is in the output.
Can have a look here:
http://maishudi.com/test3.php
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评论（4）
这行
你没有关闭标签，你正在打开另一个标签，它应该显示
This line
You're not closing the tag, you're opening another, it should read
是错误，将其更改为
is the error , change it to
在
行中，您的关闭标记实际上并未关闭。它应该是：In the line
<option value="-1">--<option>, your close tag isn't actually closing. It should read:请仔细查看输出中的第一个“选项”，您忘记关闭标签:)
Please look carefully at the first "option" in the output, you forgot to close the tag :)