Msbuild 中的 CSC 任务因命名空间错误而中止

发布于 2024-08-05 06:47:53 字数 805 浏览 4 评论 0原文

我尝试了以下操作：

 <!-- Specify the inputs by type and file name -->
<ItemGroup>
    <CSFile Include = "$(MSBuildProjectDirectory)\..\Mine.cs"/>
</ItemGroup>

<Target Name = "Compile">
    <!-- Run the Visual C# compilation using input files of type CSFile -->
       <Csc Sources="@(CSFile)" />
    <!-- Log the file name of the output file -->
    <Message Text="The output file is done"/>
</Target>

这不起作用，因为项目中使用的所有命名空间都会抛出错误。有谁知道我如何显式地从解决方案文件中获取程序集，因为路径没问题，并且如果在 Visual Studio 中加载，一切都很好。我需要编写这个脚本，而上面的内容不起作用。有明显的事故吗？

感谢您的输入:-)

我已经意识到这不会起作用，因为我拥有的文件有几个外部依赖项。因此我需要使用 devenv.exe。问题是我得到以下信息：

我得到的是命令退出时显示代码 1？我想让项目构建它所需的所有依赖 dll，而无需打开 Visual Studio。

有什么想法吗？

谢谢:-)

原文

I have attempted the following:

 <!-- Specify the inputs by type and file name -->
<ItemGroup>
    <CSFile Include = "$(MSBuildProjectDirectory)\..\Mine.cs"/>
</ItemGroup>

<Target Name = "Compile">
    <!-- Run the Visual C# compilation using input files of type CSFile -->
       <Csc Sources="@(CSFile)" />
    <!-- Log the file name of the output file -->
    <Message Text="The output file is done"/>
</Target>

This does not work as all the namespaces used in the project throw errors. Does anyone know how I can explicitly get the assemblies to pick up from the solution file, as the paths are ok and if loaded in Visual Studio all is fine. I need to script this and the above is not working. Is there an obvious mishap?

Appreciate the inpuT :-)

I have realised that this is not going to work as the file I have has several external dependancies. Hence I would need to use the devenv.exe. Problem is that I get the follwing:

What I get is that the command exits with Code 1? I want to get the project to build all the dependant dlls that it requires without having to open visual studio.

Any ideas?

Thnxes :-)

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

青丝拂面 2024-08-12 06:47:53

试试这个（添加你自己的dll引用）

<ItemGroup>
  <CSFile Include = "$(MSBuildProjectDirectory)\..\Mine.cs"/>
  <Reference Include="System.dll"/>
  <Reference Include="System.Data.dll"/>
  <Reference Include="System.Drawing.dll"/>
  <Reference Include="System.Windows.Forms.dll"/>
  <Reference Include="System.XML.dll"/>
</ItemGroup>
<Target Name = "Compile">
    <!-- Run the Visual C# compilation using input files of type CSFile -->
       <Csc Sources="@(CSFile)" 
            References="@(Reference)"
            OutputAssembly="$(builtdir)\$(MSBuildProjectName).exe"
            TargetType="exe" />
            />
    <!-- Log the file name of the output file -->
    <Message Text="The output file is done"/>
</Target>

try this (add you own dlls references)

<ItemGroup>
  <CSFile Include = "$(MSBuildProjectDirectory)\..\Mine.cs"/>
  <Reference Include="System.dll"/>
  <Reference Include="System.Data.dll"/>
  <Reference Include="System.Drawing.dll"/>
  <Reference Include="System.Windows.Forms.dll"/>
  <Reference Include="System.XML.dll"/>
</ItemGroup>
<Target Name = "Compile">
    <!-- Run the Visual C# compilation using input files of type CSFile -->
       <Csc Sources="@(CSFile)" 
            References="@(Reference)"
            OutputAssembly="$(builtdir)\$(MSBuildProjectName).exe"
            TargetType="exe" />
            />
    <!-- Log the file name of the output file -->
    <Message Text="The output file is done"/>
</Target>

回复收藏 0 原文

~没有更多了~