私有最终静态属性与私有最终属性

发布于 2024-08-05 00:55:54 字数 246 浏览 7 评论 0原文

在Java中，有什么区别：

private final static int NUMBER = 10;

和

private final int NUMBER = 10;

都是private和final，区别在于static属性。

什么更好？为什么？

原文

In Java, what's the difference between:

private final static int NUMBER = 10;

and

private final int NUMBER = 10;

Both are private and final, the difference is the static attribute.

What's better? And why?

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懵少女 2024-08-12 00:55:54

一般来说，static 表示“与类型本身相关，而不是与该类型的实例相关”。

这意味着您可以引用静态变量，而无需创建该类型的实例，并且引用该变量的任何代码都引用完全相同的数据。将此与实例变量进行比较：在这种情况下，类的每个实例都有一个独立版本的变量。例如：

Test x = new Test();
Test y = new Test();
x.instanceVariable = 10;
y.instanceVariable = 20;
System.out.println(x.instanceVariable);

打印出 10: y.instanceVariable 和 x.instanceVariable 是分开的，因为 x 和 y指代不同的对象。

您可以通过引用来引用静态成员，尽管这样做不是一个好主意。如果我们这样做：

Test x = new Test();
Test y = new Test();
x.staticVariable = 10;
y.staticVariable = 20;
System.out.println(x.staticVariable);

那么就会打印出 20 - 只有一个变量，而不是每个实例一个。如果将其写为：

Test x = new Test();
Test y = new Test();
Test.staticVariable = 10;
Test.staticVariable = 20;
System.out.println(Test.staticVariable);

这使得行为更加明显。现代 IDE 通常会建议将第二个列表更改为第三个列表。

没有理由使用内联声明来初始化如下所示的值，因为每个实例都有自己的 NUMBER 但始终具有相同的值（不可变并使用文字初始化）。这与所有实例只有一个final static 变量相同。

private final int NUMBER = 10;

因此，如果它无法更改，则每个实例拥有一份副本就没有意义。

但是，如果在这样的构造函数中初始化，那就有意义了：

// No initialization when is declared
private final int number;

public MyClass(int n) {
   // The variable can be assigned in the constructor, but then
   // not modified later.
   number = n;
}

现在，对于 MyClass 的每个实例，我们可以拥有不同但不可变的 number 值。

In general, static means "associated with the type itself, rather than an instance of the type."

That means you can reference a static variable without having ever created an instances of the type, and any code referring to the variable is referring to the exact same data. Compare this with an instance variable: in that case, there's one independent version of the variable per instance of the class. So for example:

Test x = new Test();
Test y = new Test();
x.instanceVariable = 10;
y.instanceVariable = 20;
System.out.println(x.instanceVariable);

prints out 10: y.instanceVariable and x.instanceVariable are separate, because x and y refer to different objects.

You can refer to static members via references, although it's a bad idea to do so. If we did:

Test x = new Test();
Test y = new Test();
x.staticVariable = 10;
y.staticVariable = 20;
System.out.println(x.staticVariable);

then that would print out 20 - there's only one variable, not one per instance. It would have been clearer to write this as:

Test x = new Test();
Test y = new Test();
Test.staticVariable = 10;
Test.staticVariable = 20;
System.out.println(Test.staticVariable);

That makes the behaviour much more obvious. Modern IDEs will usually suggest changing the second listing into the third.

There is no reason to have an inline declaration initializing the value like the following, as each instance will have its own NUMBER but always with the same value (is immutable and initialized with a literal). This is the same than to have only one final static variable for all instances.

private final int NUMBER = 10;

Therefore if it cannot change, there is no point having one copy per instance.

But, it makes sense if is initialized in a constructor like this:

// No initialization when is declared
private final int number;

public MyClass(int n) {
   // The variable can be assigned in the constructor, but then
   // not modified later.
   number = n;
}

Now, for each instance of MyClass, we can have a different but immutable value of number.

私有最终静态属性与私有最终属性

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很少，和 static

very little, and static

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