StructureMap 类链接 - 堆栈溢出或其他错误

发布于 2024-08-04 14:46:31 字数 1103 浏览 4 评论 0原文

这让我对许多配置感到完全困惑。我一直在阅读文档,但我就是不明白。这是我的注册代码:

ForRequestedType<SimpleWorkItemProcessor>().TheDefault.Is.OfConcreteType<SimpleWorkItemProcessor>();

ForRequestedType<WorkItemRetryProcessor>().TheDefault.Is.OfConcreteType<WorkItemRetryProcessor>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<SimpleWorkItemProcessor>())
    .WithCtorArg("busyDelay").EqualTo(TimeSpan.FromMilliseconds(20))
    .WithCtorArg("overallTimeout").EqualTo(TimeSpan.FromSeconds(60));

ForRequestedType<WorkItemQueue>().TheDefault.Is.OfConcreteType<WorkItemQueue>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<WorkItemRetryProcessor>());

事实上,它表示 IWorkItemProcessor 没有默认实例(这是正确的)。将最后一行切换为:

ForRequestedType<IWorkItemProcessor>().TheDefault.Is.OfConcreteType<WorkItemQueue>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<WorkItemRetryProcessor>());

...产生堆栈溢出异常。

如何将既实现接口又在其构造函数中采用相同接口的类链接在一起?

This has completely baffled me on a number of configurations. I keep reading the documentation, and I just don't get it. Here is my registration code:

ForRequestedType<SimpleWorkItemProcessor>().TheDefault.Is.OfConcreteType<SimpleWorkItemProcessor>();

ForRequestedType<WorkItemRetryProcessor>().TheDefault.Is.OfConcreteType<WorkItemRetryProcessor>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<SimpleWorkItemProcessor>())
    .WithCtorArg("busyDelay").EqualTo(TimeSpan.FromMilliseconds(20))
    .WithCtorArg("overallTimeout").EqualTo(TimeSpan.FromSeconds(60));

ForRequestedType<WorkItemQueue>().TheDefault.Is.OfConcreteType<WorkItemQueue>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<WorkItemRetryProcessor>());

As it is, it says there's no default instance for IWorkItemProcessor (which is correct). Switching the last line to this:

ForRequestedType<IWorkItemProcessor>().TheDefault.Is.OfConcreteType<WorkItemQueue>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<WorkItemRetryProcessor>());

...Makes a stack overflow exception.

How do you chain classes together that both implement an interface, and take in that same interface in their constructor?

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(1

风筝有风,海豚有海 2024-08-11 14:46:31

这有效,但我无法解释为什么。据我所知,第一个版本应该也能正常工作。

ForRequestedType<SimpleWorkItemProcessor>().TheDefault.Is.OfConcreteType<SimpleWorkItemProcessor>();

var retryProcessor = ForRequestedType<WorkItemRetryProcessor>().TheDefault.Is.OfConcreteType<WorkItemRetryProcessor>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<SimpleWorkItemProcessor>())
    .CtorDependency<TimeSpan>("busyDelay").Is(x => x.Object(TimeSpan.FromMilliseconds(20)))
    .CtorDependency<TimeSpan>("overallTimeout").Is(x => x.Object(TimeSpan.FromSeconds(60)));

ForRequestedType<IWorkItemProcessor>().TheDefault.Is.OfConcreteType<WorkItemQueue>()
    .CtorDependency<IWorkItemProcessor>("workItemProcessor").Is(x => x.Instance(retryProcessor));

This works, but I can't explain why. From what I know, the first version should work just as well.

ForRequestedType<SimpleWorkItemProcessor>().TheDefault.Is.OfConcreteType<SimpleWorkItemProcessor>();

var retryProcessor = ForRequestedType<WorkItemRetryProcessor>().TheDefault.Is.OfConcreteType<WorkItemRetryProcessor>()
    .CtorDependency<IWorkItemProcessor>().Is(x => x.OfConcreteType<SimpleWorkItemProcessor>())
    .CtorDependency<TimeSpan>("busyDelay").Is(x => x.Object(TimeSpan.FromMilliseconds(20)))
    .CtorDependency<TimeSpan>("overallTimeout").Is(x => x.Object(TimeSpan.FromSeconds(60)));

ForRequestedType<IWorkItemProcessor>().TheDefault.Is.OfConcreteType<WorkItemQueue>()
    .CtorDependency<IWorkItemProcessor>("workItemProcessor").Is(x => x.Instance(retryProcessor));
~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文