window.openDialog 不会删除 Linux 上的标题栏
我使用以下代码来显示弹出窗口：
var win = window.openDialog("chrome://broceliand/content/view/popup/nameMapPopup.xul",
"",
"all=no," +
"titlebar=no," +
"chrome=yes," +
"toolbar=no," +
"dialog=no," +
"resizable=no," +
"modal=yes," +
"dependent=yes," +
"top="+popupY+"px," +
"left="+popupX+"px",
args);
在 Windows 上，弹出窗口非常干净。没有剩余的共同元素。 但在 Linux 上， 标题栏 仍然保留，并且弹出窗口是可调整大小的。
I use the following code to display a popup:
var win = window.openDialog("chrome://broceliand/content/view/popup/nameMapPopup.xul",
"",
"all=no," +
"titlebar=no," +
"chrome=yes," +
"toolbar=no," +
"dialog=no," +
"resizable=no," +
"modal=yes," +
"dependent=yes," +
"top="+popupY+"px," +
"left="+popupX+"px",
args);
On windows the popup is pretty clean. There are no common elements remaining.
But on linux le titlebar still remains and the popup is resizable.
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评论（2）
尝试将
window元素上的hidechrome属性设置为true。请参阅https://developer.mozilla.org/en/xul/windowTry setting the
hidechromeattribute on thewindowelement totrue. See https://developer.mozilla.org/en/xul/window这可能是因为在 Linux 上窗口装饰器负责标题栏。这甚至可以是窗口管理器的单独程序。
弹出窗口是否需要作为单独的窗口？也许 panel 正是您正在寻找的。
That might be because on Linux the window decorator is responsible for the titlebar. This can even be a seperate program to the window manager.
Does the popup need to be as a seperate window? Perhaps panel is really what you are looking for.