正则表达式问题
我需要一些帮助来解决我遇到的一些正则表达式问题。首先，双引号 "。
"" 之间的任何内容都需要匹配。下一个问题我需要匹配以 ' 开头的任何内容，直到行尾 \n 或
没有任何想法可以匹配。
我已经尝试了各种方法，但似乎 意识到我需要将引号放在 " 和 " 之间。
I need some help with some regular expression problems I am having. First off, double quotes ".
Anything between "" needs to be matched. Next problem I need to match anything that starts with a ' till the end of a line \n or <br />.
I've tried all sorts, but nothing seems to match it. Any ideas?
Sorry guys, just realised I need the quotes to be between " and ".
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简单化：
将匹配双引号之间的任何内容，尽管它不适用于转义双引号，例如
对于 EOL 的单引号，您可以使用
更新：Sylverdrag's made a valid point;匹配您需要的引号
，然后获取匹配的第一个子组。我看到问题已经更新，提到应该使用
"- 我的答案可以很容易地适应这一点。Simplistic:
will match anything between double quotes, though it won't work with escaped double quotes such as
For the single-quote to EOL, you can use
Update: Sylverdrag's made a valid point; to match between the quotes you'd need
and then get the first subgroup of the match. I see the question's been updated to mention that
"should be used - my answer can be adapted to this easily enough.尝试：
双引号：
单引号直到行尾或
Try:
Double quotes:
Single quote till end of line or
<br/>:引号之间的任何内容
从 ' 到行尾的
anything between quotes
from ' till end of line
尝试这些正则表达式：
Try these regular expressions:
为了变得更时髦一点，只匹配双引号内的内容，而不匹配引号本身：
To get a bit more funky and match only what is inside the double quotes but not the quotes themselves: