Actionscript3 是否提供列表推导式或 lambda 演算？

发布于 2024-08-03 05:33:40 字数 549 浏览 2 评论 0原文

我正在将我在 python 中原型化的一些代码移植到 flash，虽然 actionscript 并不像我预期的那么糟糕（我听说 v3 比 v2 好很多！），但我仍然需要做一些事情看起来过于平淡/样板，例如对列表进行求和...

var a:int = 0;

for each ( var value:int in annual_saving )

    {

        a  = a + value;

    }

return a / 100;

而不是...

return reduce(lambda x,y: (x+y), self.annual_saving ) / 100

这对我来说有点太像Java了（eww Java：puke！XO###）

我只是不知道as3的酷数组求和功能吗？或者它是否理解 lambda 演算，或者列表推导式？或者提供其他一些这样简洁的符号？我是否怀疑有一种更优雅的方法可以做到这一点，或者我在这个项目的其余部分中停留在 20 世纪！？

干杯：）

罗杰。

原文

I'm porting some code I prototyped in python over to flash and while actionscript doesn't suck quite as bad as I expected (I hear v3 is quite a lot better than v2!) there's still some stuff I'm having to do that seems overly prosaic / boilerplate e.g. summing a list...

var a:int = 0;

for each ( var value:int in annual_saving )

    {

        a  = a + value;

    }

return a / 100;

as opposed to...

return reduce(lambda x,y: (x+y), self.annual_saving ) / 100

That feels a bit too much like Java for me (eww Java: puke! X-O###)

Am I simply ignorant of as3's cool array summing function? Or does it understand lambda calculus, or do list comprehensions? or provide some other such concise notation? Am I right in suspecting there is a more elegant way of doing this or am I stuck in the 20th century for the remainder of this project!?

Cheers :)

Roger.

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薆情海 2024-08-10 05:33:40

Actionscript 与 JS 非常相似。如果必须的话，您可以轻松地自己实现它：

var annual_saving = [50, 100, 50, 100];
function reduce (f, arr) {
    var a = arr[0];
    for (var i = 1; i < arr.length; i++) {
        a = f(a,arr[i]);
    }
    return a;
}
var res = reduce(function (x,y) { return x+y }, annual_saving);

您可以轻松地扩展它...语法会稍微不那么吸引人，但仍然非常简洁。

Actionscript is very similar to JS. You could easily implement it yourself if you had to:

var annual_saving = [50, 100, 50, 100];
function reduce (f, arr) {
    var a = arr[0];
    for (var i = 1; i < arr.length; i++) {
        a = f(a,arr[i]);
    }
    return a;
}
var res = reduce(function (x,y) { return x+y }, annual_saving);

You could easily extend this... the syntax will be somewhat less appealing, but still very concise.

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