撇号情况的正确注释代码
只是好奇你会如何评论这行代码：
string customerNm = customerNm.EndsWith("s") ? customerNm+= "'" : customerNm+="'s";
Just curious how you would comment this line of code:
string customerNm = customerNm.EndsWith("s") ? customerNm+= "'" : customerNm+="'s";
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评论（6）
将其放入自己的函数中，并适当地命名该函数。这应该足够清楚了。 （而且您也可以更轻松地测试它！）
Put it into its own function, and name the function appropriately. That should be clear enough. (And you can test it more easily, too!)
我根本不会评论它。按原样来说已经足够清楚了。
如果您确实发表评论，您应该解释为什么您这样做。
例如：
I would not necessarily comment it at all. It's clear enough as-is.
If you do comment it, you should explain why you do it the way you do.
E.g.:
我会用“不工作”来评论它。因为您在分配之前访问“customerNm”。
（您使用“customerNm+=...”，这意味着：创建一个新的字符串实例作为旧实例[尚未分配]和...的串联）。
这甚至不应该被编译。
我认为你的意思是：
其中 customerNm 是之前已经分配过一次的字符串。
I would comment it with "not working". Because you access 'customerNm' before you assign to it.
(You use "customerNm+=..." which means: create a new string instance as a concatenation of the old instance [which isn't assigned yet] and ...).
This shouldn't even get compiled.
I think what you mean is:
where customerNm is a string already assigned to once before.
不是您要问的问题，但您的代码似乎违反了 语法规则< /a>.
名称不应仅仅因为以“s”结尾而被视为复数名词。例如，如果詹姆斯有一只狗，那么它是詹姆斯的狗，而不是詹姆斯的狗。然而，如果两个名叫迈克的生活伴侣都有一只狗，那么它都是迈克的狗。
例外：如果多音节名称以“ess”或“ezz”声音结尾，则可以将其视为以“s”结尾的复数。如果莱纳斯有一只狗，它可以是莱纳斯的狗，尽管我相信莱纳斯的狗也是可以接受的。
Not the question you're asking, but it looks like your code violates grammar rules.
A name should not be treated like a plural noun just because it ends in 's'. For instance, if James has a dog, it's James's dog, not James' dog. However, if two life partners named Mike have a dog, it's both Mikes' dog.
Exception: if a multisyllabic name ends in as "ess" or "ezz" sound, than it can be treated like a plural ending in 's'. If Linus has a dog, it can be Linus' dog, although I believe Linus's is also acceptable.