如何从 bash 的历史记录中选择行的子集？
我经常通过 bash shell 历史记录来 grep 来查找旧命令、文件路径等。确定了感兴趣的历史记录编号后，我希望在两侧看到几行上下文，即查看历史线的子集。例如：
$ history | grep ifconfig
8408 ifconfig eth0
8572 sudo ifconfig eth0 down
我想查看第 8572 行两侧的 5 行左右。显然知道行号，我可以用 less 翻阅历史记录，但这看起来非常愚蠢。据我所知，联机帮助页似乎也没有此信息。
有没有一种简单的方法可以在 bash 中检索任意历史记录行？
Quite often I grep through my bash shell history to find old commands, filepaths, etc. Having identified the history number of interest, I would like to see a few lines of context on either side, i.e. view a subset of history lines. For example:
$ history | grep ifconfig
8408 ifconfig eth0
8572 sudo ifconfig eth0 down
I would like to look at the 5 lines or so either side of line 8572. Obviously knowing the line number I can page through the history with less, but this seems very stupid. As far as I can tell, the manpage doesn't seem to have this information either.
Is there a simple way to retrieve arbitrary lines of history in bash?
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grep 的 -C 选项提供上下文。尝试：
grep's -C option provides context. Try:
如果您只想查看特定行号，您也可以使用类似的示例，
该示例打印第 116 行到第 120 行。
If you only want to see it for specific line numbers, you can also use something like this
The example prints lines 116 through 120.
A = grep 找到的匹配项后的行数
B = grep 找到的匹配项之前的行数
您还可以将行数从 5 更改为您想要的任何数量。
A = number of lines after the match found by grep
B = number of lines before the match found by grep
You can also change the number of lines from 5 to any number you want.
输入 ctrl-r，然后输入一些字符（交互式搜索）。更多信息。
type ctrl-r, then some characters (interactive searching). More information here.
我输入
历史 | grep“840”I type
history | grep " 840"