关于C#中Fluent接口的问题

Question

我有以下课程：

public class Fluently
{
  public Fluently Is(string lhs)
  {
    return this;
  }
  public Fluently Does(string lhs)
  {
    return this;
  }
  public Fluently EqualTo(string rhs)
  {
    return this;
  }
  public Fluently LessThan(string rhs)
  {
    return this;
  }
  public Fluently GreaterThan(string rhs)
  {
    return this;
  }
}

在英语语法中，你不能有“某物等于某物”或“某物大于某物”，所以我不希望 Is.EqualTo 和Does.GreaterThan 成为可能。有什么办法限制吗？

var f = new Fluently();
f.Is("a").GreaterThan("b");
f.Is("a").EqualTo("b");        //grammatically incorrect in English
f.Does("a").GreaterThan("b");
f.Does("a").EqualTo("b");      //grammatically incorrect in English

谢谢你！

Answer 1

为了强制执行这种类型的事情，您需要多种类型（以限制从哪个上下文中可用的内容）-或者至少需要一些接口：

public class Fluently : IFluentlyDoes, IFluentlyIs
{
    public IFluentlyIs Is(string lhs)
    {
        return this;
    }
    public IFluentlyDoes Does(string lhs)
    {
        return this;
    }
    Fluently IFluentlyDoes.EqualTo(string rhs)
    {
        return this;
    }
    Fluently IFluentlyIs.LessThan(string rhs)
    {
        return this;
    }
    Fluently IFluentlyIs.GreaterThan(string rhs)
    {
        return this;
    }
}
public interface IFluentlyIs
{
    Fluently LessThan(string rhs);
    Fluently GreaterThan(string rhs);
}
public interface IFluentlyDoes
{    // grammar not included - this is just for illustration!
    Fluently EqualTo(string rhs);
}

Answer 2

在我看来，我的解决方案

public class Fluently
{
    public FluentlyIs Is(string lhs)
    {
        return this;
    }
    public FluentlyDoes Does(string lhs)
    {
        return this;
    }
}

public class FluentlyIs
{
    FluentlyIs LessThan(string rhs)
    {
        return this;
    }
    FluentlyIs GreaterThan(string rhs)
    {
        return this;
    }
}

public class FluentlyDoes
{
    FluentlyDoes EqualTo(string rhs)
    {
        return this;
    }
}

与 Gravell 的解决方案非常相似，但更容易理解。