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告诉 Ruby 程序等待一段时间

发布于 2024-08-02 09:45:50 字数 38 浏览 4 评论 0原文

如何告诉 Ruby 程序在继续执行下一行代码之前等待任意时间？

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挽袖吟 2024-08-09 09:45:50

像这样：

sleep(num_secs)

num_secs 值可以是整数或浮点数。

另外，如果您在 Rails 应用程序中编写此代码，或者已在项目中包含 ActiveSupport 库，则可以使用以下便捷语法构造更长的间隔：

sleep(4.minutes)
# or, even longer...
sleep(2.hours); sleep(3.days) # etc., etc.
# or shorter
sleep(0.5) # half a second

Like this:

sleep(num_secs)

The num_secs value can be an integer or float.

Also, if you're writing this within a Rails app, or have included the ActiveSupport library in your project, you can construct longer intervals using the following convenience syntax:

sleep(4.minutes)
# or, even longer...
sleep(2.hours); sleep(3.days) # etc., etc.
# or shorter
sleep(0.5) # half a second

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才能让你更想念 2024-08-09 09:45:50

像这样使用 sleep ：

sleep 2

这将休眠 2 秒。

小心地提出论点。如果您只是运行 sleep，该进程将永远休眠。（当您希望线程休眠直到被唤醒时，这非常有用。）

Use sleep like so:

sleep 2

That'll sleep for 2 seconds.

Be careful to give an argument. If you just run sleep, the process will sleep forever. (This is useful when you want a thread to sleep until it's woken.)

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∞梦里开花 2024-08-09 09:45:50

我发现 until 对于睡眠非常有用。例子：

> time = Time.now
> sleep 2.seconds until Time.now > time + 10.seconds # breaks when true
> # or
> sleep 2 and puts 'still sleeping' until Time.now > time + 10
> # or
> sleep 1.seconds until !req.loading # suggested by ohsully

I find until very useful with sleep. example:

> time = Time.now
> sleep 2.seconds until Time.now > time + 10.seconds # breaks when true
> # or
> sleep 2 and puts 'still sleeping' until Time.now > time + 10
> # or
> sleep 1.seconds until !req.loading # suggested by ohsully

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别念他 2024-08-09 09:45:50

像这样

sleep(no_of_seconds)

或者您可以传递其他可能的参数，例如：

sleep(5.seconds)

sleep(5.minutes)

睡眠（5.小时）

睡眠（5.天）

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握住你手 2024-08-09 09:45:50

秒/分钟/小时的实现，这是rails方法。请注意，隐式返回不是必需的，但它们看起来更干净，所以我更喜欢它们。我不确定 Rails 是否有 .days 或者是否更进一步，但这些是我需要的。

class Integer
   def seconds
      return self
   end
   def minutes
      return self * 60
   end
   def hours
      return self * 3600
   end
   def days
      return self * 86400
   end
end

之后，您可以执行以下操作：
sleep 5.seconds 睡眠 5 秒。您可以sleep 5.mines来睡5分钟。您可以sleep 5.hours来睡5个小时。最后，您可以执行 sleep 5.days 来睡眠 5 天...您可以添加任何返回 self * 值（该时间范围内的秒数）的方法。
作为练习，尝试实施几个月！

Implementation of seconds/minutes/hours, which are rails methods. Note that implicit returns aren't needed, but they look cleaner, so I prefer them. I'm not sure Rails even has .days or if it goes further, but these are the ones I need.

class Integer
   def seconds
      return self
   end
   def minutes
      return self * 60
   end
   def hours
      return self * 3600
   end
   def days
      return self * 86400
   end
end

After this, you can do:
sleep 5.seconds to sleep for 5 seconds. You can do sleep 5.minutes to sleep for 5 min. You can do sleep 5.hours to sleep for 5 hours. And finally, you can do sleep 5.days to sleep for 5 days... You can add any method that return the value of self * (amount of seconds in that timeframe).
As an exercise, try implementing it for months!

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暗恋未遂 2024-08-09 09:45:50

sleep 6 将休眠 6 秒。如果需要更长的持续时间，您还可以使用 sleep(6.minutes) 或 sleep(6.hours)。

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韶华倾负 2024-08-09 09:45:50

的示例。

require 'sidekiq'

class PlainOldRuby
  include Sidekiq::Worker

  def perform(how_hard="super hard", how_long=10)
    sleep how_long
    puts "Workin' #{how_hard}"
  end
end

这是使用 sleep 和 sidekiq sleep 10 秒并打印出 "Working super hard"

This is an example of using sleep with sidekiq

require 'sidekiq'

class PlainOldRuby
  include Sidekiq::Worker

  def perform(how_hard="super hard", how_long=10)
    sleep how_long
    puts "Workin' #{how_hard}"
  end
end

sleep for 10 seconds and print out "Working super hard" .

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