在asp.net mvc中，当某些代码运行时我将如何显示页面？
如果我想在某些脚本运行时显示加载页面，我该怎么做？
看起来，当控制器的代码执行完成时，就会呈现一个视图，但我需要向用户显示一些内容，因为代码正在执行相当多的操作。
感谢您的指点。
If I wanted to display a loading page while some script was running, how would I go about it?
It seems that a view is rendered when the controller's code has finished executing, but I need there to be something displayed to the user as the code is doing a fair amount.
Thanks for any pointers.
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您要么需要按照 Jason 的建议在 jQuery 调用中加载该页面，并希望它不会超时，要么将正在执行的代码移至独立组件中；通常是一个 Windows 服务，然后与其通信以开始处理并在完成后接收消息（我通常使用 MSMQ）。
You'll either need to load that page in a jQuery call, as suggested by Jason, and hope it doesn't time out, or move the code that is being executed into a standalone component; typically a Windows Service, and then communicate with it to start it processing and to receive a message when it's done (I generally use MSMQ).
您不应在 Web 请求中运行长时间任务。
相反，您必须执行以下操作：
这是一个示例（不过针对WebForms）。但不是启动新线程，而是从 ASP.NET 池中获取一个线程。
YOU SHOULD NOT RUN LONG TASKS IN WEB REQUEST.
Instead you have to do following:
Here is one example (for WebForms though). But instead of starting new thread obtain one from ASP.NET pool.