Html Helper RenderPartial 如何工作？如何实现一个可以从部分视图引入内容的助手？
当您使用 Html.RenderPartial 时，它会获取要渲染的视图的名称，并在该位置渲染其内容。
我想实现类似的东西。我希望它获取您想要渲染的视图的名称以及一些其他变量，并在容器中渲染内容。
例如：
public static class WindowHelper
{
public static string Window(this HtmlHelper helper, string name, string viewName)
{
var sb = new StringBuilder();
sb.Append("<div id='" + name + "_Window' class='window'>");
//Add the contents of the partial view to the string builder.
sb.Append("</div>");
return sb.ToString();
}
}
有人知道如何做到这一点吗？
When you use Html.RenderPartial is takes the name of the view you want to render, and renders it's content in that place.
I would like to implement something similar. I would like it to take the name of the view you want to render, along with some other variables, and render the content within a container..
For example:
public static class WindowHelper
{
public static string Window(this HtmlHelper helper, string name, string viewName)
{
var sb = new StringBuilder();
sb.Append("<div id='" + name + "_Window' class='window'>");
//Add the contents of the partial view to the string builder.
sb.Append("</div>");
return sb.ToString();
}
}
Anyone know how to do this?
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评论（3）
RenderPartial 扩展被编程为直接渲染到 Response 对象...您可以在它们的源代码中看到这一点：
这意味着如果您稍微改变一下方法，您可能可以实现您想要的。 您可以执行以下操作，而不是将所有内容附加到 StringBuilder：
请注意，包含 System.Web.Mvc.Html 允许您访问 RenderPartial() 方法。
The RenderPartial extensions are programmed to render directly to the Response object... you can see this in the source code for them:
This means that if you change your approach a little bit, you can probably accomplish what you want. Rather than appending everything to a StringBuilder, you could do something like this:
Note that including System.Web.Mvc.Html allows you access to the RenderPartial() methods.
我们正在 MVC 2 中修复此问题。您将能够调用 Html.Partial() 并以字符串形式获取视图的实际内容。
We are fixing this in MVC 2. You will be able to call Html.Partial() and get the actual contents of the view as a string.
为什么不创建第二个视图并在其中包含部分视图，将名称作为 ViewData 或模型等传递。
类似的东西：
希望有帮助，
担
Why not create a second view and have the partial inside that, pass Name as ViewData or in model etc..
Something like:
Hope that helps,
Dan