直接从方法获取选择器？ NSSelectorFromMethod([[SomeClass someObject] 方法])?

发布于 2024-08-01 22:03:59 字数 12 浏览 5 评论 0 原文

是否可以？

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隐诗 2024-08-08 22:03:59

或者，使用：

NSSelectorFromString(@"myMethodName");

Alternatively, use:

NSSelectorFromString(@"myMethodName");

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感性 2024-08-08 22:03:59

您在标题中的示例不太清楚。

但我们开始了。所有类的所有选择器都位于同一名称空间中。这意味着 Bar 类上的 doFoo 或 Baz 类上的 doFoo 都将是相同的唯一选择器。这意味着您无需为获取选择器而费心处理类。两种不错的方法。

NSSelectorFromString(@"doFoo");  // If you have the selector name as a string.
@selector(foFoo);  // If it is selector constant inlined in your code.

您的问题还可能涉及如何从方法返回选择器。由于选择器是 obj-c 中的一等公民，因此我们可以将它们作为任何变量传递，并从方法中返回它们。选择器的类型是SEL。

-(SEL)selectorFromFoo:(Foo*)aFoo;  // Declare a method returning a selector.

SEL sel = [myBar selectorFromFoo:myFoo];    // Get a selector.
[myBar proformSelector:sel withObject:nil]; // Perform this selector

Your example in the header is not quite clear.

But here we go. All selectors for all classes lives int he same namespace. Meaning doFoo on the class Bar, or doFoo on the class Baz will both be the same unique selector. This means you do not need to bother with the class in order to get a selector. Two nice ways to do it.

NSSelectorFromString(@"doFoo");  // If you have the selector name as a string.
@selector(foFoo);  // If it is selector constant inlined in your code.

Your question could also refer to how to return selectors from a method. Since selectors are first class citizens in obj-c, we can pass them around as any variables, and return them from methods. The type of a selector is SEL.

-(SEL)selectorFromFoo:(Foo*)aFoo;  // Declare a method returning a selector.

SEL sel = [myBar selectorFromFoo:myFoo];    // Get a selector.
[myBar proformSelector:sel withObject:nil]; // Perform this selector

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