Django 通讯应用程序

发布于 2024-08-01 21:26:28 字数 77 浏览 8 评论 0 原文

django 有没有新闻通讯应用程序，允许用户订阅或取消订阅新闻通讯？我想要一个易于使用并通过 Django 管理员进行管理的应用程序。

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棒棒糖 2024-08-08 21:26:29

尝试 djangolist

DjangoList 是一个 Django 应用程序，它将
允许进行群发邮件和管理
用户可以从中获取时事通讯
订阅/取消订阅。 DjangoList 是
目前正在开发中，尚未
准备使用。

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风启觞 2024-08-08 21:26:29

也许，也许不是。拥有一个在新闻通讯（但这是想象的）和订阅者（用户或名字/姓氏/电子邮件地址/密码上的外键）之间具有多对多关联的应用程序并不会太难。

你的模型会是这样的：

from django.db import models
from django.contrib.auth.models import User

class Subscriber(models.Model):
    user = models.ForeignKey(User)
    email = models.EmailField()

    def __unicode__(self):
        return "User %s" % (self.user.username, )

    @models.permalink
    def get_absolute_url(self):
        return ('subscriber', None, {'object_id' : self.id})

    class Meta:
        ordering = [ "id" ]

class Newsletter(models.Model):
    name = models.CharField(max_length=80)
    subscribers = models.ManyToManyField('Subscriber')
    # .... Other stuff

    def __unicode__(self):
        return "Newsletter %s" % (self.name, )

    @models.permalink
    def get_absolute_url(self):
        return ('newsletter', None, {'object_id' : self.id})

    class Meta:
        ordering = [ "id" ]

你的 urls.py 会是这样的：

from django.conf.urls.defaults import *
from django.views.generic.simple import direct_to_template

urlpatterns = patterns('',
    url(r'^subscriber/(?P<object_id>\d+)/
这足以让你继续吗？
, views.subscriberview, name='subscriber_view'),
    url(r'^newsletter/(?P<object_id>\d+)/
这足以让你继续吗？
', views.newsletterview,name='newsletter_view'),
    url(r'^site_media/(?P<path>.*)
这足以让你继续吗？
, 'django.views.static.serve', {'document_root': MEDIA_ROOT}),
)

这足以让你继续吗？

Maybe, maybe not. It wouldn't be too hard to have an app that has a many-to-many association between a Newsletter (however that is imagine) and a Subscriber (foreign key on User or firstName/lastName/emailAddress/password).

Your models would be something like this:

from django.db import models
from django.contrib.auth.models import User

class Subscriber(models.Model):
    user = models.ForeignKey(User)
    email = models.EmailField()

    def __unicode__(self):
        return "User %s" % (self.user.username, )

    @models.permalink
    def get_absolute_url(self):
        return ('subscriber', None, {'object_id' : self.id})

    class Meta:
        ordering = [ "id" ]

class Newsletter(models.Model):
    name = models.CharField(max_length=80)
    subscribers = models.ManyToManyField('Subscriber')
    # .... Other stuff

    def __unicode__(self):
        return "Newsletter %s" % (self.name, )

    @models.permalink
    def get_absolute_url(self):
        return ('newsletter', None, {'object_id' : self.id})

    class Meta:
        ordering = [ "id" ]

Your urls.py would be something like this:

from django.conf.urls.defaults import *
from django.views.generic.simple import direct_to_template

urlpatterns = patterns('',
    url(r'^subscriber/(?P<object_id>\d+)/
Is that enough to get you going?
, views.subscriberview, name='subscriber_view'),
    url(r'^newsletter/(?P<object_id>\d+)/
Is that enough to get you going?
', views.newsletterview,name='newsletter_view'),
    url(r'^site_media/(?P<path>.*)
Is that enough to get you going?
, 'django.views.static.serve', {'document_root': MEDIA_ROOT}),
)

Is that enough to get you going?

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