重载“=” 使 obj2 = obj1 时不会调用相等性
我有一个名为 MemoryManager 的类，
它应该实现一个简单的智能指针，（计数引用）；
我有一个向量，在其中存储请求的指针，并将指针的索引返回给调用者。
当用户创建 MemoryManager 类型的指针时，他调用名为 modded_malloc(size_t) 的初始化函数，创建一个 MemoryManager obj，分配一个内存空间并将其存储到数据中，增加计数，并将对象存储到 global_MM_vecotr 中，并将索引作为指针返回，当使用尝试使用间接寻址（->）时，我从向量中返回适当的实际指针，根据到索引值..
class MemoryManager
{
public:
//operators overloading prototypes
private:
void* data;
int count ;
};
std::vector<MemoryManager*> global_MM_vecotr;
void* MemoryManager::operator=( void* x)
{
// some code here
}
我面临的问题是我重载了几个运算符，但是当我尝试运行“=”运算符下面的代码时不会被调用.. 有人可以向我指出问题吗？
//the main code
{
MemoryManager* obj1 = (MemoryManager*) x->fun1(4); //fun1 returns an index to a MemoryManager obj in a vector;
MemoryManager* obj2 = obj1 ;
}
编辑：已经尝试了以下操作，没有任何改变
{
MemoryManager*obj1 = (MemoryManager*) x->fun1(4); //fun1 returns an index to a Class obj in a vector;
MemoryManager*obj2 ;
*obj2 = *obj1;
}
{
MemoryManager* obj1 = ( MemoryManager*) x-> fun1(4);
MemoryManager* obj2;
obj2.operator =(*obj1);
}
i have this class called MemoryManager,
it is supposed to implement a simple smart pointer, (count reference);
i have a vector where i store the requested pointers,and i return the index of the pointer to the caller..
when a user creates a pointer of type MemoryManager he calls an initializer function called modified_malloc(size_t) , create a MemoryManager obj, alloc a memory space and store it into data,increase count, and store the object into global_MM_vecotr , and return the index as a pointer , when the use tries to use indirection ( ->) i return the appropriate real pointer from the vector, according to the index value..
class MemoryManager
{
public:
//operators overloading prototypes
private:
void* data;
int count ;
};
std::vector<MemoryManager*> global_MM_vecotr;
void* MemoryManager::operator=( void* x)
{
// some code here
}
the problem i am facing is that i overloaded a couple of operators, however when i try to run the code below the "=" operator doesn't get called..
can some1 point the problem out to me..
//the main code
{
MemoryManager* obj1 = (MemoryManager*) x->fun1(4); //fun1 returns an index to a MemoryManager obj in a vector;
MemoryManager* obj2 = obj1 ;
}
Edit: already tried the following , no change
{
MemoryManager*obj1 = (MemoryManager*) x->fun1(4); //fun1 returns an index to a Class obj in a vector;
MemoryManager*obj2 ;
*obj2 = *obj1;
}
{
MemoryManager* obj1 = ( MemoryManager*) x-> fun1(4);
MemoryManager* obj2;
obj2.operator =(*obj1);
}
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（4）
可能是一个技术问题，但您不是分配一个
ClassA，而是分配一个ClassA*（即指针）。 我可能离这里很远，但这就是我应该归咎的地方。Might be a technicality, but you're not assigning a
ClassA, you're assigning aClassA*(ie, a pointer). I might be way off here, but this is where I'd lay the blame.我怀疑您正在使用 void 指针，以便您可以输入任何类型的对象。 我建议使用 模板 与 boost::check 库。
I suspect you're using the void pointer so that you can enter any kind of object. I'd recommend using a template instead combined with the boost::check library.
在您的代码中，您已经为采用
void*的MemoryManager类定义了operator=。您的示例代码正在初始化
ClassA指针，而不是分配给MemoryManager实例。您的代码没有被调用有三个原因。
ClassA，而不是您实际为其提供了operator=的MemoryManager。From you code, you have defined
operator=for theMemoryManagerclass taking avoid*.Your example code is initializing
ClassApointers and not assigning toMemoryManagerinstances.There are three reasons why your code is not being called.
ClassAand notMemoryManagerwhich you have actually provided theoperator=for.请参阅规范，您不能覆盖指针基本操作。
See spec, you cannot override pointer basic operations.