使用 PHP 发布到 Blogger
我在让 PHP 的 Blogger API 正常工作时遇到问题。
我需要的是能够将新的博客文章发布到我的博客帐户。 我使用的代码取自 Google API 页面: http://code.google.com/intl/ nl/apis/blogger/docs/1.0/developers_guide_php.html
这是我的代码:
<?
require_once 'Zend/Loader.php';
Zend_Loader::loadClass('Zend_Gdata');
Zend_Loader::loadClass('Zend_Gdata_Query');
Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
$user = '[email protected]';
$pass = 'password';
$service = 'blogger';
$client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $service, null,
Zend_Gdata_ClientLogin::DEFAULT_SOURCE, null, null,
Zend_Gdata_ClientLogin::CLIENTLOGIN_URI, 'GOOGLE');
$gdClient = new Zend_Gdata($client);
$blogID = '7973737751295446679';
function createPublishedPost($title='Hello, world!', $content='I am blogging on the internet.')
{
$uri = 'http://www.blogger.com/feeds/' . $blogID . '/posts/default';
$entry = $gdClient->newEntry();
$entry->title = $gdClient->newTitle($title);
$entry->content = $gdClient->newContent($content);
$entry->content->setType('text');
$createdPost = $gdClient->insertEntry($entry, $uri);
$idText = split('-', $createdPost->id->text);
$newPostID = $idText[2];
return $newPostID;
}
createPublishedPost();
?>
我收到的错误是“致命错误:在 C:\ 中的非对象上调用成员函数 newEntry() xampp\htdocs\HelloWorld\blogger2.php on line 21'
任何人都可以帮助我或给我一个如何使用 PHP 发布到博客的工作代码示例吗?
I'm having a problem getting the Blogger API for PHP to work.
What I need is to be able to post a new blogpost to my bloggeraccount.
The code I'm using is taken from the Google API page here :
http://code.google.com/intl/nl/apis/blogger/docs/1.0/developers_guide_php.html
Here is my code :
<?
require_once 'Zend/Loader.php';
Zend_Loader::loadClass('Zend_Gdata');
Zend_Loader::loadClass('Zend_Gdata_Query');
Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
$user = '[email protected]';
$pass = 'password';
$service = 'blogger';
$client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $service, null,
Zend_Gdata_ClientLogin::DEFAULT_SOURCE, null, null,
Zend_Gdata_ClientLogin::CLIENTLOGIN_URI, 'GOOGLE');
$gdClient = new Zend_Gdata($client);
$blogID = '7973737751295446679';
function createPublishedPost($title='Hello, world!', $content='I am blogging on the internet.')
{
$uri = 'http://www.blogger.com/feeds/' . $blogID . '/posts/default';
$entry = $gdClient->newEntry();
$entry->title = $gdClient->newTitle($title);
$entry->content = $gdClient->newContent($content);
$entry->content->setType('text');
$createdPost = $gdClient->insertEntry($entry, $uri);
$idText = split('-', $createdPost->id->text);
$newPostID = $idText[2];
return $newPostID;
}
createPublishedPost();
?>
The error I'm getting is 'Fatal error: Call to a member function newEntry() on a non-object in C:\xampp\htdocs\HelloWorld\blogger2.php on line 21'
Can anyone help me out or give me a working code sample of how to post to blogger using PHP ?
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将
$gdClient
移至函数体修复了某些问题,但您还必须将$blogID
移至函数体。Moving the
$gdClient
to the function body fixed something, but you also have to move the$blogID
into the function body.您的
$gdClient
变量在createPublishedPost
函数外部进行初始化:在函数内部,默认情况下不存在在函数外部定义的变量。
关于这一点,你可以看看变量作用域 手册页。
这意味着函数内部不存在
$gdClient
; 因此,它是null
; 所以,不是一个对象——这解释了您收到的错误消息。要自行检查,您可以
在函数的开头使用:它将允许您查看它是什么类型的数据; 如果它不是您愿意使用的类的实例,那么这不是一个好兆头;-)
您可能想要:
createPublishedPost
函数global
位于函数内部(因此函数可以“看到”外部声明的变量)< /em>我认为第一个解决方案可能是最干净的;-)
作为旁注,您可能需要配置
error_reporting
级别(另请参阅),因此,当您使用未声明的变量时,您会得到一个E_NOTICE
——在这种情况下,您应该得到一个;-)您可能还想启用
display_errors
,在您的开发计算机上,如果它尚未打开 - 似乎是,因为您收到了致命错误消息一开始可能看起来有点烦人,但是,一旦你习惯了它,它真的很棒:可以更快地检测到这类东西;-)
它还有助于检测变量名称中的拼写错误^^
它让你的代码更加干净!
Your
$gdClient
variable is intanciated outside of thecreatePublishedPost
function :Inside a function, the variables that have been defined outside of it don't exist by default.
About that, you can take a look at the Variable scope page of the manual.
This means
$gdClient
doesn't exist inside the function ; hence, it isnull
; so, not an object -- which explains the error message you are getting.To check that by yourself, you can use
at the beginning of the function : it will allow you to see what kind of data it is ; if it's not an instance of the class you are willing to use, it's not a good sign ;-)
You might want to either :
createPublishedPost
functionglobal
inside the function (so the function can "see" the variable as declared outside)The first solution is probably the cleanest one, I think ;-)
As a sidenote, you might want to configure your
error_reporting
level (see also), so you get anE_NOTICE
when you are using a variable that is not declared -- in this case, you should have gotten one, for instance ;-)You might also want to enable
display_errors
, on your development machine, if it's not already on -- seems to be, as you got the Fatal error messageIt might seem a bit annoying at the beginning, but, once you get used to it, it is really great : allow to detect that kind of stuff a lot quicker ;-)
And it also helps detect typos in variable names ^^
And it makes you code way cleaner !