INSERT INTO..SELECT..ON DUPLICATE KEYS 不明确的 ID

Question

我有下表：

mysql> SELECT *  FROM  `bright_promotion_earnings`;
+----+----------+------------+----------+-------+
| id | promoter | generation | turnover | payed |
+----+----------+------------+----------+-------+
|  1 |        4 |          1 |       10 |     0 | 
|  3 |        4 |          5 |      100 |     0 | 
|  4 |        4 |          3 |    10000 |     1 | 
|  5 |        4 |          3 |      200 |     0 | 
+----+----------+------------+----------+-------+
4 rows in set (0.00 sec)

有一个唯一的键（发起人、一代、已付费）：

+---------------------------+------------+------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table                     | Non_unique | Key_name   | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+---------------------------+------------+------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| bright_promotion_earnings |          0 | promoter_2 |            1 | promoter    | A         |           2 |     NULL | NULL   | YES  | BTREE      |         | 
| bright_promotion_earnings |          0 | promoter_2 |            2 | generation  | A         |           4 |     NULL | NULL   |      | BTREE      |         | 
| bright_promotion_earnings |          0 | promoter_2 |            3 | payed       | A         |           4 |     NULL | NULL   |      | BTREE      |         | 
+---------------------------+------------+------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
3 rows in set (0.00 sec)

现在我想通过使用paid=1（如果存在）更新相同条目来将发起人的每笔收入标记为已付费。

因此，如果我想将发起人 4 的收入标记为已付款，那么表格应该如下所示：

+----+----------+------------+----------+-------+
| id | promoter | generation | turnover | payed |
+----+----------+------------+----------+-------+
|  4 |        4 |          3 |    10200 |     1 | 
|  6 |        4 |          5 |      100 |     1 | 
|  7 |        4 |          1 |       10 |     1 | 
+----+----------+------------+----------+-------+
3 rows in set (0.00 sec)

这是我当前的方法（没有微不足道的 DELETE）：

INSERT INTO 
    bright_promotion_earnings
    (
        promoter,
        generation,
        turnover,
        payed
    )
SELECT 
    commission.promoter,
    commission.generation,
    commission.turnover as turnover2,
    '1' as payed
FROM  
    bright_promotion_earnings as commission
WHERE  
    promoter=4
    AND payed=0
ON DUPLICATE KEY UPDATE turnover=turnover+turnover2;

但 mysql 一直告诉我营业额不明确：

#1052 - Column 'turnover' in field list is ambiguous

有人有吗？提示，因为我无法为要插入的表添加别名。

如何为我要插入的表指定一个名称，以便 mysql 可以识别该列？

提前致谢。

Answer 1

你在两个表中都有一个营业额字段，所以mysql无法决定你在最后一行指的是哪一个。