iPhone Dev：激活 tabBar 按钮的视图

发布于 2024-07-30 10:43:42 字数 340 浏览 1 评论 0原文

我有一个应用程序，它有一个处理所有视图的 tabBar。在第一个视图中，我有一个登录过程。当该过程完成时，我想自动转到第二个 tabBar 视图，而不让用户单击其各自的 tabBar 按钮。

到目前为止，我所要做的就是用以下命令突出显示该按钮：

myTabBar.selectedItem = [myTabBar.items objectAtIndex:1];

但我不知道如何自动将与该按钮相关的第二个视图放在前面。到目前为止，用户必须在按钮亮起（选中）时按下按钮。

知道如何做到这一点吗？是否可以？我们将不胜感激。谢谢。

原文

I have an application that has a tabBar that handles all the views. In the first view I have a login process. When that process finishes I want to go automatically to the second tabBar view without making the user to click in its respective tabBar button.

All I've got until now is to highlight the button with this:

myTabBar.selectedItem = [myTabBar.items objectAtIndex:1];

But I have no idea about how to bring the second view related to that button to the front, automatically. Until now the user has to press the button when it gets lighted (selected).

Any idea about how to do this? Is it possible? It would be much appreciated. Thanks.

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淡水深流 2024-08-06 10:43:42

使用 selectedViewController 或 selectedIndex 相应 UITabBarController。

为了回应对此答案的评论，我提供了一个如何实现这一点的示例：

id firstViewController = [[FirstViewController alloc] initWithNibName:@"FirstView" bundle:[NSBundle mainBundle]];
id secondViewController = [[SecondViewController alloc] initWithNibName:@"SecondView" bundle:[NSBundle mainBundle]];

self.tabBarController = [[UITabBarController alloc] init];
self.tabBarController.viewControllers = [NSArray arrayWithObjects:firstViewController, secondViewController, nil];

[firstViewController release];
[secondViewController release];

// Select the second tab bar item and its view
self.tabBarController.selectedIndex = 1;

[self.window addSubview:tabBarController.view];
[self.window makeKeyAndVisible];

在我的测试中，似乎使用 UITabBarController 的 selectedViewController 方法来设置当前视图不会更新 selectedIndex 属性（新视图是显示但选定的 UITabBarItem 未更改）。这与文档中承诺的行为形成对比。但是，使用上面代码片段中演示的 selectedIndex 方法应该可以正常工作。

Use the selectedViewController or selectedIndex methods of the corresponding UITabBarController.

In response to the comments on this answer, I have provided an example of how this might be accomplished:

id firstViewController = [[FirstViewController alloc] initWithNibName:@"FirstView" bundle:[NSBundle mainBundle]];
id secondViewController = [[SecondViewController alloc] initWithNibName:@"SecondView" bundle:[NSBundle mainBundle]];

self.tabBarController = [[UITabBarController alloc] init];
self.tabBarController.viewControllers = [NSArray arrayWithObjects:firstViewController, secondViewController, nil];

[firstViewController release];
[secondViewController release];

// Select the second tab bar item and its view
self.tabBarController.selectedIndex = 1;

[self.window addSubview:tabBarController.view];
[self.window makeKeyAndVisible];

In my testing, it seems that using the selectedViewController method of UITabBarController to set the current view does not update the selectedIndex property (the new view is displayed but the selected UITabBarItem is not changed). This is in contrast to the behavior promised in the documentation. Using the selectedIndex method as demonstrated in the code snippet above should work fine, however.

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