有没有办法在 List中查找对象的属性 使用包含?

发布于 2024-07-30 10:29:10 字数 2557 浏览 5 评论 0原文

我在想如何才能知道列表中是否已存在某个对象。 我在列表中添加“newPerson”(Person 类的实例),但检查列表中是否存在 newPerson 内容/属性。

这篇文章工作正常:

        List<Person> people = this.GetPeople();
        if (people.Find(p => p.PersonID  == newPerson.PersonID
                    && p.PersonName  == newPerson.PersonName) != null)
        {
            MessageBox.Show("This person is already in the party!");
            return;
        }

首先,我想简化/优化上面这段丑陋的代码。 所以我想到了使用Contains方法。

        List<Person> people = this.GetPeople();
        if (people.Contains<Person>(newPerson)) //it doesn't work!
        {
            MessageBox.Show("This person is already in the party!");
            return;
        }

上面的第二个代码不起作用,我认为它是比较对象引用而不是对象内容/属性。

Stackoverflow 上和 链接文本 中的某人是谈论使用实现 IEqualityComparer 的类。 我尝试了一下,但现在代码更大了! 类似于:

    public class PersonComparer : IEqualityComparer<Person>
    {
    // Products are equal if their names and i numbers are equal.
    public bool Equals(Person x, Person y)
    {

        // Check whether the compared objects reference the same data.
        if (Object.ReferenceEquals(x, y)) return true;

        // Check whether any of the compared objects is null.
        if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null))
            return false;

        // Check whether the products' properties are equal.
        return x.PersonID == y.PersonID && x.PersonName == y. PersonName;
    }

    // If Equals() returns true for a pair of objects,
    // GetHashCode must return the same value for these objects.

    public int GetHashCode(Person p)
    {
        // Check whether the object is null.
        if (Object.ReferenceEquals(p, null)) return 0;

        // Get the hash code for the Name field if it is not null.
        int hashPersonName = p.PersonName == null ? 0 : p.PersonName.GetHashCode();
        int hashPersonID = i.PersonID.GetHashCode();

        // Calculate the hash code for the i.
        return hashPersonName ^ hashPersonID;
    }

}

并使用此比较器:

        PersonComparer comparer = new PersonComparer();
        if (people.Contains<Person>(newPerson, comparer))
        {
            MessageBox.Show("This person is already in the party.");
            return;
        }

是否有更小的方法可以在列表中查找对象的属性?

I was wandering how can I find out if an object already exists in my List.
I'm adding "newPerson" (instance of Person class) in a List, but checking if newPerson contents/properties exists or not in the List.

This piece works fine:

        List<Person> people = this.GetPeople();
        if (people.Find(p => p.PersonID  == newPerson.PersonID
                    && p.PersonName  == newPerson.PersonName) != null)
        {
            MessageBox.Show("This person is already in the party!");
            return;
        }

First of all, I wanted to simplify/optimize this ugly code above. So I thought about using Contains method.

        List<Person> people = this.GetPeople();
        if (people.Contains<Person>(newPerson)) //it doesn't work!
        {
            MessageBox.Show("This person is already in the party!");
            return;
        }

The second code above doesn't work, I think it's comparing objects references and not object contents / properties.

Someone here on Stackoverflow and in link text was talking about using an class that implements IEqualityComparer. I gave it a try, but the code is much bigger now!
Something like:

    public class PersonComparer : IEqualityComparer<Person>
    {
    // Products are equal if their names and i numbers are equal.
    public bool Equals(Person x, Person y)
    {

        // Check whether the compared objects reference the same data.
        if (Object.ReferenceEquals(x, y)) return true;

        // Check whether any of the compared objects is null.
        if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null))
            return false;

        // Check whether the products' properties are equal.
        return x.PersonID == y.PersonID && x.PersonName == y. PersonName;
    }

    // If Equals() returns true for a pair of objects,
    // GetHashCode must return the same value for these objects.

    public int GetHashCode(Person p)
    {
        // Check whether the object is null.
        if (Object.ReferenceEquals(p, null)) return 0;

        // Get the hash code for the Name field if it is not null.
        int hashPersonName = p.PersonName == null ? 0 : p.PersonName.GetHashCode();
        int hashPersonID = i.PersonID.GetHashCode();

        // Calculate the hash code for the i.
        return hashPersonName ^ hashPersonID;
    }

}

and to use this comparer:

        PersonComparer comparer = new PersonComparer();
        if (people.Contains<Person>(newPerson, comparer))
        {
            MessageBox.Show("This person is already in the party.");
            return;
        }

Is there a smaller way to find my object's properties in a List?

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评论(2

疯了 2024-08-06 10:29:11

听起来您的 Person 类应该实现 IEquatable。 是的,这是(有点)更多的代码,但是您不必每次想要比较 2 个人对象时都重复它。

列表的Contains方法默认使用对象的Equals方法。 因此,如果正确实现 IEquatable,则不必传递自定义 IEqualityComparer。

It sounds like your Person class should implement IEquatable<Person>. Yes, it is (a bit) more code, but then you don't have to repeat it each time you want to compare 2 person objects.

The Contains method of the list uses the Equals method of the object by default. So if you implement IEquatable correctly, you do not have to pass a custom IEqualityComparer.

冰火雁神 2024-08-06 10:29:11

ExistsAny 与谓词一起使用:

List<Person> people = this.GetPeople();
if (people.Exists(p => p.PersonID  == newPerson.PersonID
                       && p.PersonName  == newPerson.PersonName))
{  
    MessageBox.Show("This person is already in the party!");
    return;
}

这将适用于 .NET 2.0(并且可以使用匿名方法转换为 C# 2)。 更多 LINQy 解决方案是 Any

List<Person> people = this.GetPeople();
if (people.Any(p => p.PersonID  == newPerson.PersonID
                    && p.PersonName  == newPerson.PersonName))
{
    MessageBox.Show("This person is already in the party!");
    return;
}

Use Exists or Any with a predicate:

List<Person> people = this.GetPeople();
if (people.Exists(p => p.PersonID  == newPerson.PersonID
                       && p.PersonName  == newPerson.PersonName))
{  
    MessageBox.Show("This person is already in the party!");
    return;
}

That will work with .NET 2.0 (and can be converted to C# 2 using an anonymous method). The more LINQy solution is Any:

List<Person> people = this.GetPeople();
if (people.Any(p => p.PersonID  == newPerson.PersonID
                    && p.PersonName  == newPerson.PersonName))
{
    MessageBox.Show("This person is already in the party!");
    return;
}
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