如何初始化静态 std::map?

发布于 2024-07-30 04:24:49 字数 1190 浏览 6 评论 0原文

我创建了一个仅消息窗口类,并且尝试将 HWND 映射回具有这些句柄的对象。 我试图使用属于该类的私有静态 std::map 来做到这一点,如下所示:

MyClass.h:

class CMyClass
{
    ...

private:
    HWND        m_hWnd;
    HINSTANCE   m_hInstance;
    LPCSTR      m_szClassName;

    static std::map<HWND, CMyClass*> s_mapHandles;

    ...
};

MyClass.cpp:

std::map<HWND, CMyClass*> CMyClass::s_mapHandles;

但是当我尝试添加到地图后,程序崩溃。 我尝试了三种不同的形式,它们都给出了相同的错误:

...
m_hWnd = ::CreateWindowEx(0, m_szClassName, "Message Window", 0, 0, 0, 0, 0, HWND_MESSAGE, 0, m_hInstance, 0);
s_mapHandles.insert(pair<HWND, CMyClass*>(m_hWnd, this));

...
s_mapHandles.insert(s_mapHandles.end(), pair<HWND, CMyClass*>(m_hWnd, this));

甚至

...
s_mapHandles[m_hWnd] = this;

在每种情况下,在调用 _Root() 时都会发生崩溃,该调用尝试返回 _Parent(_Myhead );; _Parent(_Myhead) 返回 (_Nodepref)(*_Myhead)._Parent ,但失败,因为 _Myhead 为 null。

如何初始化地图,使其头部非空,并且我可以插入东西而不会崩溃? 如果我解释得不好,我很抱歉 - 我是 C++ 新手。

I've made a message-only window class, and I'm trying to map HWNDs back to the objects with those handles. I'm trying to do that using a private static std::map<HWND, CMyClass*> belonging to the class, like this:

MyClass.h:

class CMyClass
{
    ...

private:
    HWND        m_hWnd;
    HINSTANCE   m_hInstance;
    LPCSTR      m_szClassName;

    static std::map<HWND, CMyClass*> s_mapHandles;

    ...
};

MyClass.cpp:

std::map<HWND, CMyClass*> CMyClass::s_mapHandles;

but when I try to add to the map, the program crashes. I've tried three different forms, and they all give the same error:

...
m_hWnd = ::CreateWindowEx(0, m_szClassName, "Message Window", 0, 0, 0, 0, 0, HWND_MESSAGE, 0, m_hInstance, 0);
s_mapHandles.insert(pair<HWND, CMyClass*>(m_hWnd, this));

or

...
s_mapHandles.insert(s_mapHandles.end(), pair<HWND, CMyClass*>(m_hWnd, this));

or even

...
s_mapHandles[m_hWnd] = this;

In each case, there crash occurs at a call to _Root() which tries to return _Parent(_Myhead); _Parent(_Myhead) returns (_Nodepref)(*_Myhead)._Parent which fails because _Myhead is null.

How do I initialise the map, such that its head is non-null and I can insert things without it crashing? Apologies if I've explained this badly - I'm new to C++.

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评论(6

み青杉依旧 2024-08-06 04:24:49

只是出于好奇。 窗口句柄不为空吗? 因为如果窗口句柄返回为 null,则插入将失败。

Just out of curiosity. Is the window handle not null? Because if the window handle comes back as null then the insert will fail.

橘寄 2024-08-06 04:24:49

原来的问题可能已经解决了,但我碰巧遇到了类似的问题(没有静态部分)。 我曾经将映射放在函数内部,然后将其移至类变量中。 插入地图时我也遇到了崩溃。 事实证明,我需要删除所有已编译的对象并从头开始重新编译。 然后一切都会按预期进行。

The original problem may be already solved, but I happen to run in to similar problem (without the static part). I used to have the map inside of a function, then moved it to a class variable. I also got crashes when inserting to the map. It turns out that I needed to delete the all the compiled objects and restart compiling from scratch. Then everything works as expected.

缘字诀 2024-08-06 04:24:49

您是否从另一个静态初始化对象的构造函数中使用它?

阅读 C++ FAQ Lite - 10.12 什么是“静态初始化顺序惨败”?

Are you using it from the constructor of another statically initialized object?

Read C++ FAQ Lite - 10.12 What's the "static initialization order fiasco"?

草莓味的萝莉 2024-08-06 04:24:49

您根本不需要初始化它,它应该默认初始化。

You don't need to initialize it at all, it should be initialized by default.

安稳善良 2024-08-06 04:24:49

这可能同时已经解决,但仅供参考:这是问题背后实际问题的另一个解决方案:您可以将自定义数据存储在任何窗口的 GWL_USERDATA 字段中(我相信使用 ::SetWindowLong API 函数,如果我记住正确)。 如果您将 CMyClass 指针放在那里,而不是通过映射将其与 HWND 关联起来,那么,您根本不需要映射,而且效率更高,因为您所需要做的就是对指针进行类型转换,而不是昂贵的映射地图查找。

This has probably been solved in the meantime, but just for reference: Here is another solution for the actual problem behind the question: You can store custom data in the GWL_USERDATA field of any Window (I believe using the ::SetWindowLong API function if I remember correctly). If you put your CMyClass pointer in there instead of associating it with the HWND via a map, well, you don't need the map at all, and it is more efficient since all you need to do is typecast the pointer instead of an expensive map lookup.

盛夏已如深秋| 2024-08-06 04:24:49

我的 C++ 有点生疏,但我认为没有任何理由在 .cpp 文件中包含该行。 事实上,由于它不是静态成员,我不确定这会导致什么样的行为。 但就像我说的,我生疏了——我可能会错过一些东西。

My C++ is a little rusty, but I don't think there's any reason for having that line in your .cpp file. In fact, since it's not a static member, I'm not sure what kind of behavior that would lead to. But like I said, I'm rusty - I could be missing something.

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