如何在 /bin/sh 生成的 CGI 中获取变量 + 阿帕奇
我正在按照 CGI 脚本
echo "Content-type: text/html; charset=UTF-8\n\n"
echo "<HTML><HEAD><TITLE>title</TITLE></HEAD>"
echo "<BODY>"
echo "<FORM ACTION="http://exapmle.com/page2.cgi" NAME="PAGE1" METHOD="POST">"
echo "input:<INPUT TYPE=text NAME="data1" SIZE=10 MAXLENGTH=10>"
echo "<INPUT TYPE=submit NAME=nbtn VALUE='GO TO PAGE2'>"
echo "</FORM>"
echo "</BODY>"
echo "</HTML>"
How to get valid in CGI made by /bin/sh + Apache 进行编码 我很高兴给我样品线
I'm coding following CGI script
echo "Content-type: text/html; charset=UTF-8\n\n"
echo "<HTML><HEAD><TITLE>title</TITLE></HEAD>"
echo "<BODY>"
echo "<FORM ACTION="http://exapmle.com/page2.cgi" NAME="PAGE1" METHOD="POST">"
echo "input:<INPUT TYPE=text NAME="data1" SIZE=10 MAXLENGTH=10>"
echo "<INPUT TYPE=submit NAME=nbtn VALUE='GO TO PAGE2'>"
echo "</FORM>"
echo "</BODY>"
echo "</HTML>"
How to get valiable in CGI made by /bin/sh + Apache
I am glad gime me sample cord
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在 CGI 脚本中,您将其作为 main 的参数接收,因此它应该位于 argv 指向的某个位置
Apache 就像您一样运行 cgi:
并且参数是在argv中,所以这样:
将输出
In the CGI script, you receive it as a parameter to main, so it should be in some place pointed by argv
Apache runs the cgi just like you:
And the parameters are in argv, so this:
Will output