“Lambda 参数不在范围内” 使用 SimpleRepository 的 Single 方法时出现异常
我正在尝试使用 SimpleRepository 基于非 ID 属性执行提取。 这是我正在使用的 Customer 类:
[Serializable]
public class Customer : IEntity<Guid>
{
public Guid ProviderUserKey { get; set; }
public Guid ID
{
get; set;
}
}
我正在使用启用了迁移的 SimpleRepository。 抛出“Lambda 参数不在范围内”的代码如下:
public class CustomerRepository :
ICustomerRepository
{
private readonly IRepository _impl;
public CustomerRepository(string connectionStringName)
{
_impl = new SimpleRepository(connectionStringName,
SimpleRepositoryOptions.RunMigrations);
}
public Customer GetCustomer(string userName)
{
var user = Membership.GetUser(userName);
// Code to guard against a missing user would go here
// This line throws the exception
var customer = _impl.Single<Customer>(c => c.ProviderUserKey.Equals(user.ProviderUserKey));
// Code to create a new customer based on the
// ASP.NET Membership user would go here
return customer;
}
}
我不确定在 LINQ 表达式编译中的哪个点抛出此消息,但我正在空数据库上运行此示例。 模式生成足以创建表结构,但无法计算表达式。
有谁知道我可能做错了什么?
谢谢!
I'm attempting to use the SimpleRepository to perform a fetch based on a non-ID property. Here's the Customer class I'm using:
[Serializable]
public class Customer : IEntity<Guid>
{
public Guid ProviderUserKey { get; set; }
public Guid ID
{
get; set;
}
}
I'm using SimpleRepository with migrations turned on. The code that throws the "Lambda Parameter not in scope" is below:
public class CustomerRepository :
ICustomerRepository
{
private readonly IRepository _impl;
public CustomerRepository(string connectionStringName)
{
_impl = new SimpleRepository(connectionStringName,
SimpleRepositoryOptions.RunMigrations);
}
public Customer GetCustomer(string userName)
{
var user = Membership.GetUser(userName);
// Code to guard against a missing user would go here
// This line throws the exception
var customer = _impl.Single<Customer>(c => c.ProviderUserKey.Equals(user.ProviderUserKey));
// Code to create a new customer based on the
// ASP.NET Membership user would go here
return customer;
}
}
I'm not sure at what point in the LINQ expression compilation this throws, but I am running this example on an empty database. The schema generations gets far enough to create the table structure, but can't evaluate the expression.
Does anyone know what I might be doing wrong?
Thanks!
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我收到过有关此问题的报告 - 您可以将此(和您的代码)添加为问题吗?
I've had reports of this - can you add this (and your code) as an issue please?