python 3 中的 Expat 解析

发布于 2024-07-29 05:19:34 字数 635 浏览 6 评论 0原文

import xml.parsers.expat

def start_element(name, attrs):
    print('Start element:', name, attrs)

def end_element(name):
    print('End element:', name)

def character_data(data):
    print('Character data: %s' % data)

parser = xml.parsers.expat.ParserCreate()
parser.StartElementHandler = start_element
parser.EndElementHandler = end_element
parser.CharacterDataHandler = character_data
parser.ParseFile(open('sample.xml'))

上面的代码适用于 python 2.6，但不适用于 python 3.0 - 任何让它在 python 3 中工作的想法都非常感谢。我在 ParseFile 行上收到的错误是 TypeError: read() did not return a bytes object (type=str)

原文

import xml.parsers.expat

def start_element(name, attrs):
    print('Start element:', name, attrs)

def end_element(name):
    print('End element:', name)

def character_data(data):
    print('Character data: %s' % data)

parser = xml.parsers.expat.ParserCreate()
parser.StartElementHandler = start_element
parser.EndElementHandler = end_element
parser.CharacterDataHandler = character_data
parser.ParseFile(open('sample.xml'))

The above works in python 2.6 but not in python 3.0 - any ideas to make it work in python 3 much appreciated. The error I get on the ParseFile line is TypeError: read() did not return a bytes object (type=str)

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別甾虛僞 2024-08-05 05:19:34

您需要将该文件作为二进制文件打开：

parser.ParseFile(open('sample.xml', 'rb'))

you need to open that file as binary:

parser.ParseFile(open('sample.xml', 'rb'))

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对不⑦ 2024-08-05 05:19:34

我在尝试将 xmltodict 模块与 Python 3 一起使用时遇到了这个问题。在 Python 2.7 下我没有任何问题但在 Python 3 下我遇到了同样的错误。解决方案与@SilentGhost 建议的相同：

import xmltodict

def convert(xml_file, xml_attribs=True):
    with open(xml_file, "rb") as f:    # notice the "rb" mode
        d = xmltodict.parse(f, xml_attribs=xml_attribs)
        return d

I ran into this problem while trying to use the xmltodict module with Python 3. Under Python 2.7 I had no problems but under Python 3 I got this same error. The solution is the same that was suggested by @SilentGhost:

import xmltodict

def convert(xml_file, xml_attribs=True):
    with open(xml_file, "rb") as f:    # notice the "rb" mode
        d = xmltodict.parse(f, xml_attribs=xml_attribs)
        return d

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